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Jobisdone [24]
3 years ago
12

the gas tank on a car has a capacity of 75 liters. on a full tank of gas the car travels 325 miles. what is the gas mileage in m

iles per liter
Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0

The gas mileage in miles per liter is 4.3_ (Repeating decimal) miles/liter

I found this by doing 325 / 75 = 4.3_ (the 3 is repeating)

Hope that helps!!


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An iPod sold for $300, which was 200% of the actual cost. What was the actual cost?
fgiga [73]

Answer:

If $300 is 200%, half of that would be 100%. Thus, $150 is the correct answer.

Step-by-step explanation:

3 0
2 years ago
Show all the steps!<br><br>3+2x=13-3x
Goshia [24]

Answer:

x=2

Step-by-step explanation:

3+2x=13-3x

 +3x      +3x

3+5x=13

-3      -3

5x=10

/5    /5

x=2

Hope this helps! :D

7 0
3 years ago
Read 2 more answers
What is 1/8 of the sum of 28 and 43
victus00 [196]
1/8 of anything is just 1/8 * anything, so   \bf \cfrac{1}{8}\times (28+43)
3 0
3 years ago
A lab is testing the amount of a certain active chemical compound in a particular drug that has been recently developed. The man
Mazyrski [523]

Answer:

The 95% confidence interval is "87.94, 91.86".

Step-by-step explanation:

The given values are:

Sample batches,

n = 25

Sample mean concentration,

\bar{x} = 89.9 mg

Amount of chemical,

σ = 5

α = 0.05

The critical value from Z table will be:

=  Z(\frac{\alpha}{2} )

=  Z(\frac{0.05}{2} )

=  1.96

Now,

The confidence interval will be:

=  \bar{x}  \pm Z(\frac{\alpha}{2} )\times \frac{\sigma}{\sqrt{n} }

On substituting the values, we get

=  89.9 \pm Z(\frac{0.05}{2})\times \frac{5}{\sqrt{25}}

=  89.9 \pm Z(\frac{0.05}{2})\times \frac{5}{5}

=  89.9 \pm1.96\times 1

Lower limit will be:

=  89.9 -1.96\times 1

=  87.94

Upper limit will be:

=  89.9 +1.96\times 1

=  91.86

7 0
2 years ago
Anser and i'll gige brainly
Vilka [71]

Answer:

b² - 4ac > 0

Step-by-step explanation:

Conditions for the discriminant

• If b² - 4ac > 0 then 2 real and distinct roots

• If b² - 4ac = 0 then 2 real and equal roots

• If b² - 4ac < 0 then no real roots

Here the roots are x = 0 and x = 4

That is 2 real and distinct roots , then

b² - 4ac > 0

7 0
2 years ago
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