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sasho [114]
3 years ago
6

The scatter plot shows the relationship between the test scores of a group of students and the number of hours they exercise in

a week:
On a grid, Label Hours of Exercise on x axis and Test Scores on y axis. The title of the graph is Test Scores and Exercise. The scale on the x axis shows the numbers from 0 to 10 at increments of 1, and the scale on the y axis shows numbers from 0 to 100 at increments of 10. Dots are made at the ordered pairs 1.1, 12 and 1, 30 and 2.1, 21 and 2.5, 42 and 3.5, 30 and 3.5, 45 and 4, 55 and 5, 45 and 5.5, 60 and 5.5, 70 and 6.5, 40 and 7, 50 and 7.5, 80 and 8, 75, and 8.5, 60 and 9, 75. The ordered pair 9, 15 is circled and labeled as T. All the other points are put in an oval and labeled as P
.
Part A: What is the group of points labeled P called? What is the point labeled T called? Give a possible reason for the presence of point T. (5 points)

Part B: Describe the association between students' test scores and the number of hours they exercise. (5 points)

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:

It is going by -34 each time so

Step-by-step explanation:

Sedbober [7]3 years ago
6 0
It’s going to be -13 every time
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A line passes through the point (–7, 5) and has a slope of 1/2. Which is another point that the line passes through?
IgorLugansk [536]
Selection C is appropriate.

_____
The change in x for the offered points is -6, -2, 16, 20, so the slope of 1/2 will make the change in y be -3, -1, 8, 10. When added to 5, these values are 2, 4, 13, 15. Only 13 matches the second coordinate of the given answer, so only (9, 13) will be a point on the line.

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Two planes just took off from Charlotte NC. The first plane is traveling 1.5 times as fast as the second plane. After traveling
Ksju [112]

Givens

Slower plane

r = r

t = 2.5 hours

d = d

Faster Plane

r_faster = 1.5 * r

t = 2.5 hours

d1 = d + 127.5

The  time is the same for both

t = d/r

d1/r1 = d/r

(d+ 127.5)/1.5r = d/r   Multiply each side by r

(d + 127.5)/1.5 = d       Multiply both sides by 1.5

d + 127.5 = 1.5d          Subtract d from both sides.

127.5 = 1.5d - d    

127.5 = 0.5d              Divide by 0.5

127.5 / 0.5 = d

255 = d

Now you can go back and figure out the rates.

First find d1

d1 = d + 127.5

d1 = 255 + 127.5

d1 = 382.5

<em><u>Rate of the slower plane</u></em>

d = 255

t = 2.5 hours

r = d/t

r = 255/2.5

r = 102 miles per hour.

<em><u>Faster plane</u></em>

d1 = 382.5 miles

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r1 = d/t

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5 0
3 years ago
Find the quotient (line over 42 is repeating)
strojnjashka [21]
 The correct answer is:  [C]:  " \frac{21}{11} " . 
_____________________________________________________

<span>Explanation:
_____________________________________________________
</span>
Let us begin by converting the:  
"0.42 (with the "repeating bar on the digits, "42") " ;  

into a fraction, as follows:
______________________________________________________
   Let  x = 0.42424242424242424242424242424242....

100x = 42.42424242424242424242424242424242....
______________________________________________________
    
         100x = 42.42424242424242424242424242424242....
    –         x =   0.42424242424242424242424242424242...
______________________________________________________
          99x = 42.000000000000000000000000000000.... ;

         →   99x = 42 ;  

Divide each side of the equation by " 99 " ;  
       to isolate "x" on one side of the equation; & to solve for "x" ; 
______________________________________________________
         →  99x / 99 = 42/99 = (42 ÷ 3) / (99 ÷ 3) = 14/ 33; 

         →  x = "\frac{14}{33}" .

So;  "0.42 (with a repeating bar over the digits, "42" ;

           is equal to:  "\frac{14}{33}" 
________________________________________________
 So, rewrite the question/problem being asked:
________________________________________________
  "Find the quotient:  
________________________________________________
   \frac{14}{33}  ÷ \frac{2}{9}  ;

=  \frac{14}{33} * \frac{9}{2}  ;

Note:  The "14" cancels to a "7" <span>; and</span> the "2" cancels to a "1" ; 
       →  {since:  " 14 ÷ 2 = 7 " ; and since:  " 2 ÷ 2 = 1 "} ;

Note : The "33" cancels to an "11" ; and the "9" cancels to a "3" ;
        →  {since:  " 33 ÷ 3 = 11 " ; and since:  " 9 ÷ 3 = 3 "} ;

And we can rewrite the problem as:
____________________________________________________
 
 " \frac{7}{11}  * \frac{3}{1} "  ;

  =  \frac{(7*3)}{(11*1}   =  \frac{21}{11} ; 

            → which is:  Answer choice:  [C]:  " \frac{21}{11} " .
____________________________________________________
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