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Sauron [17]
3 years ago
15

The sum of twice a number and 6

Mathematics
2 answers:
Vlada [557]3 years ago
7 0
I looked it up and I got 4 not for sure though
Alex787 [66]3 years ago
4 0

Answer:

The answer to this question is 4.

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11/21 as a decimal and a percent
pochemuha

11/21 written as a decimal would be 0.52381 and in percent, it would be 52.381%.

To solve percent, since the total or 1/1 is 100%, we have to remember that the answer is less than 100%. So, we move 2 decimal places right to make it into percent. Then, the answer is 52.381.

To solve percent, you would do 100/21. Then, you would get 4.7619047619. You multiply that by 11 and get 52.381. But, you have to move 2 places left since fractions are tens, hundreds. So, you would get 0.52381.

8 0
3 years ago
in a company 95% of the workers are women if 220 people work for the company who aren't women how many workers are there in all?
dybincka [34]
So 5% of workers are not women, and 220 workers are not women, so 220 is 5% of the total workers. 220 is 5% of 4400, so there are 4400 workers in all.
7 0
2 years ago
This is the 4th question
gavmur [86]

Answer:

a) There are 9 outcomes.

b) **i have attached the tree diagram**

c) 1/9

d) 1/9

Step-by-step explanation:

Both events (choosing a shirt and choosing pants) are not mutually exclusive (disjoint). Meaning that both events can occur at the same time.

a) For a sequence of two events in which the first event can occur <em>m</em> ways and the second event can occur <em>n</em> ways, the events together can occur a total of <em>m</em> • <em>n</em> ways. So for this problem, you would do 3 • 3 which equals 9.

b) **tree diagram is attached**

c) Because there are two different events occurring (choosing a shirt and choosing pants) you need to multiply using the Multiplication Rule for Independent Events : P(A and B) = P(A) * P(B)

The probability of event A occurring (choosing a red shirt) is 1/3 and the probability of event B occurring (choosing brown pants) is also 1/3.

1/3 * 1/3 = 1/9

d) You would do the same thing here as part c.

The probability of event A occurring (choosing a blue shirt) is 1/3 and the probability of event B occurring (choosing blue pants) is again 1/3.

1/3 * 1/3 = 1/9

I hope this was helpful!! :)

4 0
2 years ago
6r-2(r+8)=11<br> Solve equation
pav-90 [236]

6r-2(r+8)=11\ \ \ \ |\text{use distributive property}\\\\6r-2(r)-2(8)=11\\\\6r-2r-16=11\ \ \ \ \ |+16\\\\4r=27\ \ \ \ \ |:4\\\\r=6.75

4 0
3 years ago
Explanation plsss..​
ollegr [7]

Answer:

You will need 20 sides to complete the loop.

Step-by-step explanation:

The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop

We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV

With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.

108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.

This means that each polygon is rotated 18 degrees relative to it's neighbour.

With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.

4 0
3 years ago
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