3x² -x+4=0
We can use quadratic formula
a=3, b= -1, c=4

Answer:
y=2/3x+4/3
Step-by-step explanation:
<h3>
Answer: 14s^4 - 7s^2 + 15</h3>
====================================================
Work Shown:
(12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)
12s^4-6s^2+4s+6s^4-4s+27-4s^4-s^2-12
(12s^4+6s^4-4s^4)+(-6s^2-s^2)+(4s-4s)+(27-12)
14s^4-7s^2+0s+15
14s^4-7s^2+15
Note: don't forget to distribute the negative to every term in the last parenthesis
Answer:
area of circle=πr²=1.3mi²
we have
area of sector=∅/360×πr²
0.7mi²×360=∅1.3
∅=0.7×360/1.3=193.846°×π/180=387.7 radian
Answer:
45°
Step-by-step explanation:
Using the cosine ratio in the right triangle
cosB =
=
=
, hence
B =
(
) = 45°