Answer:
-45
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Answer:
1 1 1 1
Step-by-step explanation:
Okay hey ill help you let me figure out how to type the equation out for you
The First Graph represents the situation.
The runner goes a lot of distance in a short amount of time (Demonstrated by the steep incline of the first portion). When the runner is tying their shoe, the distance remains the same, thus eliminating the second graph and the last graph because the last graph doesn't show the beginning of the problem. Finally, we know that the runner is slower after tying their shoe, this means the incline of the line would be far less as steep (Meaning the slope would be smaller). The only graph that depicts all of these, is the first one.
I Hope this Helps!
-Sinnamin
Answer: t= 460.52 minutes
Step-by-step explanation:Q'=Q/100
Q'= rate in and out of water
Finding the differential equation
Let Q'(t)= The quantity of dye in the tank for t time
But rate in=0 Q/200 ×2=Q'
Q'/Q=-1/100
Dividing by Q gives
Ln/Q/ + c = -1/100 + c1
Integrating both sides gives
Ln/Q/ = -(1/100)t + c2
But c+c1=C2= A constant
Q=C2e(-t/100)
200e-(t/100)
t= ln200
t=460.52minutes
