Find the perimeter of the polygon. Round your answer to the nearest tenth.

Mathematics

1 answer:

lubasha [3.4K]3 years ago

3 0

Answer:

Perimeter is 38.8 units and approximately 39 units

Step-by-step explanation:

Given: Graph

To find: perimeter of the polygon

Solution:

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

As per the graph,

point P is (-2,11)

point Q is (-4,6)

point R is (2,0)

point S is (1,7)

point T is (8,7)

$PQ=\sqrt{(-4+2)^2+(6-11)^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{29}=5.4\,\,units\\QR=\sqrt{(2+4)^2+(0-6)^2}=\sqrt{(6)^2+(-6)^2}=\sqrt{72}=8.5\,\,units\\RS=\sqrt{(1-2)^2+(7-0)^2}=\sqrt{(-1)^2+(7)^2}=\sqrt{50}=7.1\,\,units\\ST=\sqrt{(8-1)^2+(7-7)^2}=\sqrt{(7)^2+(0)^2}=\sqrt{49}=7\,\,units\\PT=\sqrt{(8+2)^2+(7-11)^2}=\sqrt{(10)^2+(-4)^2}=\sqrt{116}=10.8\,\,units$

Perimeter refers to sum of lengths of all the sides.

Perimeter = $5.4+8.5+7.1+7+10.8=38.8$

Or approximately 39 units

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tekilochka [14]

Answer:

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Step-by-step explanation:

the equation for finding the slope of a line when given two points is $\frac{y_2-y_1}{x_2-x_1}$ , aka the change in y over the change in x.

pick one of your coordinate pairs to be $y_2\\$ and $x_2$ . it doesn't matter which coordinate pair you choose as long as you keep them as $y_2\\$ and $x_2$ . the remaining coordinate pair will be $y_1$ and $x_1$ .

for this example, i'll use (2, 10) for $y_2\\$ and $x_2$ and (6, 7) for $y_1$ and $x_1$ .

**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for $y_2\\$ and 2 for $x_2$ ). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.

first, start by plugging in the y-value from the coordinate pair of your choosing in for $y_2\\$ . since i chose (2, 10) for $y_2\\$ and $x_2$ , i'll plug in 10 for $y_2\\$ .

$\frac{y_2-y_1}{x_2-x_1}$ ⇒ $\frac{10-y_1}{x_2-x_1}$