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Nataly [62]
3 years ago
8

12 < k + 11 The solution of the inequality is

Mathematics
2 answers:
Marianna [84]3 years ago
5 0
Ya and that’s basically it

madam [21]3 years ago
4 0

k  >  1

Step-by-step explanation:

1) Subtract 11 from both sides.

12 - 11 < k

2) Subtract 12 - 11 to 1.

1 < k

3) Switch sides.

k > 1

Therefor the answer is, k > 1.

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PLS SOMEONE LOOK AT THE PHOTO I POSTED AND ANSWER AS SOON AS POSSIBLE PLS ITS ASKING FOR X= AND Y= NOT AN EQUATION JUST PLS ANSW
34kurt

We can solve it, but we can't actually use the interactive system they want you to use.  Let's see if we can guide you through it.

My guess is you can control the lines by dragging the two points on the line.

Let's make the green line y = 2x + 3

When x=0 we get y=3, point (0,3).   That's the y intercept, 3 up on the y axis.  Drag one green point there.

When x=2 we get y=7, point (2,7), two to the right, seven  up.  Drag the other green point there.   The green line is now y = 2x + 3.

Similarly the red line is made y = -3x + 3.    When x=0, y=3, point (0,3).  [Surprise!]   When x=2, y=-3, point (2,-3).  Drag the red points to (0,3) and (2,-3).

We already saw where they meet, at (0,3), x=0, y=3, the y intercept of both lines.

Answer: x=0, y=3

8 0
4 years ago
...... trying to find domain, range rel max rel min end behavior inc intervals dec intervals. zeros..... I'm a mom trying to hel
Fiesta28 [93]

Answer:

The values are evaluated below.

Step-by-step explanation:

Given function is

-x^4-7x^3-12x^2

We have to find the domain, range, rel max, rel min, end behaviour, increasing or decreasing intervals and zeros of polynomial.

Domain:

The domain of a function is the set of all possible values of x for the given function.

Here domain is set of all real numbers R.

Range:

The range is the resulting y-values we get after substituting all the possible x-values.From the graph we see that

The range is -\infty

Relative maxima and minima of a function,  are the largest and smallest value of the function on an entire domain of function.

Relative max of -x^4-7x^3-12x^2 is 0 at x=0

and \frac{3}{512}(133\sqrt57-471) at x=\frac{-21}{8}-\frac{\sqrt57}{8}

Relative min is

\frac{-3}{512}(471+133\sqrt57) at x=\frac{-21}{8}+\frac{\sqrt57}{8}

From the graph we see that

End behaviour is  As \\x->\infty, f(x)->-\infty\\x->-\infty, f(x)->-\infty\\

Increasing intervals and decreasing intervals are

Increasing: \frac{1}{8}(\sqrt57-21)

Decreasing: \frac{1}{8}(-21-\sqrt57)  

Zeroes are :

-x^4-7x^3-12x^2=0

⇒ (-x^2)(x^2+7x+12)=0

⇒(-x^2)(x+3)(x+4)=0

Hence, zeroes are 0, 0, -3, -4



3 0
4 years ago
Read 2 more answers
Given n = 875 and pˆ = 0.45, find the margin of error E that corresponds to a 95% confidence level.
sveticcg [70]

Answer:

The margin of error E that corresponds to a 95% confidence level is: E=0.03297

Step-by-step explanation:

The propocion is p = 0.45

The sample size n = 875

95% confidence level

Level of significance = 1-level of confidence

Level of significance = 1-0.95 = 0.05

The formula for the error is:

E = Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}

The value for Z_{0.05/2} =Z_{0.0250}= 1.96 according to the normal table

So:

E = 1.96\sqrt{\frac{0.45(1-0.45)}{875}}\\\\SE=0.03297

4 0
3 years ago
For an acute angle 0, the equation sin(0) = cos(6) is true. What is the value of ? Show or explain your answer
weqwewe [10]

Answer:

\theta =84

Step-by-step explanation:

Given

sin(\theta) = cos(6)

Required

Find \thata\theta

In trigonometry:

If sin(A) = cos(B), then

A + B = 90

So, we have:

\theta + 6 = 90

Collect Like Terms

\theta + 6 -6= 90-6

\theta = 90-6

\theta =84

6 0
3 years ago
Consider the inequality-5(x+7)&lt;-10 write an inequality representing the solution for x
GrogVix [38]

Answer:

<h2>x > -5</h2>

Step-by-step explanation:

-5(x + 7) < -10            <em>use the distributive property </em><em>a(b + c) = ab + ac</em>

(-5)(x) + (-5)(7) < -10

-5x - 35 < -10         <em>add 35 to both sides</em>

-5x < 25         <em>change the signs</em>

5x > - 25       <em>divide both sides by 5</em>

x > -5

6 0
3 years ago
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