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Romashka [77]
3 years ago
11

One year, the population of a city was 127,000. Several years later it was 129,540. Find the percent increase.

Mathematics
2 answers:
Finger [1]3 years ago
7 0

Answer: 2%

Step-by-step explanation: Method 1

Express the ending population as a percentage of the starting population:  

127000 /129540= 1.02

1.02×100=  102%

Subtract the starting 100% to get the percent increase:

102%−100%= 2%  

​

Romashka-Z-Leto [24]3 years ago
4 0

Answer:

2%

Step-by-step explanation:

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Simplify eighth root of y squared
NARA [144]

Answer:

<u>The simplified expression is y raised to the 2/8 power</u>

Step-by-step explanation:

Let's recall that one of the properties of fractional exponents is:

x ^ a/b = ᵇ√x ᵃ

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⁸√y² = y ^2/8

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5 0
3 years ago
I need to know the answer
Elena L [17]

9514 1404 393

Answer:

  D.  105 ft²

Step-by-step explanation:

The total surface area is the sum of the base area and the triangular face areas.

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  A = s²

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4 0
3 years ago
What is the area of the white region? Steps please and thank you!
DIA [1.3K]

Answer:the ANS to 4 significant figures is 51.92

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5 0
3 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
3 years ago
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