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Svetradugi [14.3K]
3 years ago
9

ILL GIVE U STUFFFFF PLZZZZZZZZZZZ ANSWER ITTTTTTTTT

Mathematics
1 answer:
belka [17]3 years ago
5 0

Answer:

Slope: -\frac{3}{4}

Y-intercept: 399

Slope-intercept form: y=-\frac{3}{4}x+399

Step-by-step explanation:

1. The equation in Standard form is given in the problem:

3y+4y=1596

2. Then, to write the equation of the line in slope-intercept form  y=mx+b, where <em>m</em> is the slope and <em>b</em> is the y-intercept, you must solve for <em>y</em> as you can see below:

4y=-3x+1596\\y=\frac{-3x+1596}{4}\\y=-\frac{3}{4}x+399

3. Therefore, the slope and the y-intercept are:

m=-\frac{3}{4}\\b=399

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Olin [163]

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given the equation y-3=1/2 (x+6) in what point-slope form, identity the equation of the same line in standard form
seraphim [82]
Hello there! Your answer should be y=1/2x+6!
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Explanation: 
y-3=1/2 (x+6) {Now use the distributive property: [a(b+c)=ab+ac]}
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Please tell me in the comments section below if I helped you!
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7 0
3 years ago
A dietitian wants to know the average time spent on breakfast in a primary school. The dietitian randomly samples 25 students an
blsea [12.9K]

Answer:

The right options are:

a. The margin of error is 0.632

f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Select one or more:</em>

<em>a. The margin of error is 0.632</em>

<em>b. The margin of error is 1264.</em>

<em>C. The margin of error is 0.600.</em>

<em>d. We believe that the true mean time spent on breakfast is between 11.968 and 13.232 minutes.</em>

<em>e. If we take many other samples from this population, 95% of them will have a sample mean that is between 11968 and 13232.</em>

<em>f. There is a 95% chance that the true mean is between 11.968 and 13.232 minutes.</em>

The margin of error can be calculated from the bounds of the confidence interval as:

E=\dfrac{UL-LL}{2}=\dfrac{13.232-11.968}{2}=\dfrac{1.264}{2}=0.632

As the confidence interval is calculated at 95% confidence, we are 95% confident that the true mean is within the calculated interval. We are not 100% confident although (that's why Option d is false).

This interval does not give us information about the sampling distribution (option e is false).

8 0
3 years ago
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