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Leno4ka [110]
3 years ago
13

Write the equation for an exponential function, in the form y = A x B^2, whose graph passes through the coordinate points (1, 7.

5) and (3, 16.875)
plzzzz help
Mathematics
1 answer:
Tasya [4]3 years ago
4 0
Y=5(1.5)^x
I divided 16.875 by 7.5, which is 2.25 Since the multiplier was used twice, I found out the square root of 2.25, which is 1.5. So now we know that the multiplier is 5.
Then I divided 7.5 by 1.5 to get the initial value, since 7.5 is the value in the first spot. 7.5 divided by 1.5 is 5.
Multiplier = 1.5
Initial Value = 5
y=5(1.5)^x

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Step-by-step explanation:

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If a ball is thrown straight up into the air with an intial velocity of $$ ft/s, its height in feet after $$ seconds is given by
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Step-by-step explanation:

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On a particular day, 112 of 280 passengers on a particular DTW-LAX flight used the e-ticket check-in kiosk to obtain boarding pa
Sonja [21]

Answer:

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Population of 280, which means that N = 280

112 use e-ticket check-in kiosk, which means that k = 112

Sample of eight passengers means that n = 8

Find the approximate hypergeometric probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

This is P(X = 4). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,280,8,112) = \frac{C_{112,4}*C_{168,4}}{C_{280,4}} = 0.2348

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

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3 years ago
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Step-by-step explanation:

6 0
3 years ago
Pls pls pls help if ur good with angles and sides ​
liq [111]

Answer:

∆PQR: Equilateral Triangle

∆PRT: Scalene Triangle

∆TQS: Isosceles Triangle

∆QNP: Right Triangle

Step-by-step explanation:

∆PQR is an Equilateral Triangle because all of its angles are equal (60°).

∆PRT is a Scalene Triangle because none of its sides are equal.

The triangle above it is equilateral, and one side length is 14, meaning all of its side lengths are 14.

This makes the top of ∆PRT 14. The hypotenuse is given and it’s 18.

The last side left is clearly shorter than both, meaning none of the sides are equal.

∆TQS is an Isosceles Triangle because 2 angles are equal.

The base angles are both 76°.

∆QNP is a Right Triangle because segment QN and PR are perpendicular, creating two 90° angles on both sides.

For number 10, I suggest using a graphing calculator or desmos to graph the points. (Or you can just add the points but I suggest graphing).

From there, you can count the length of each side.

Segment DE: 9

Segment EF: 8

Segment FD: 10

This makes ∆DEF in number 10 a Scalene Triangle because none of its sides are equal.

For number 11, I also suggest graphing the points and counting the sides.

Segment DE: 7

Segment EF: 9

Segment FD: 7

This makes ∆DEF in number 11 an Isosceles Triangle because 2 of its sides are equal.

Hope this helps! :)

4 0
3 years ago
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