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8090 [49]
3 years ago
12

The first two terms of a sequence are 4 and 12.   If the sequence is arithmetic, what is the next term?   If the sequence is geo

metric, what is the next term?
Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Case 1:  20; Case 2:  36

Case 1:  arithmetic sequence

The common difference is 8.  Notice that 4 + 8 = 12.

a(1) = 4; a(2) = 12; a(3) = 20; etc.

The common next term (3rd term) is 20.

Case 2:  geometric sequence

The common ratio is 3.  Notice that 4*3 = 12.

Multiplying this second term by the common ratio (3) results in the third term:  36.

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(5k − 1 + 2k3) − (6k3 − 3k2 − 8) + (8k3 − 2k2 − 7k)
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P-&gt;q is false and p is true.<br> q is<br> a.true<br> b.false
kirill [66]

Answer:

Choice b. q has to be false.

Step-by-step explanation:

Consider the truth table of p \implies q (p implies q).

  • p is true and q is true: p \implies q would be true.
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  • p is false and q is true: p \implies q would be true.
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3 years ago
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3 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
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