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2 years ago

I need help with this question

Mathematics

2 answers:

motikmotik2 years ago

8 0

Answer:1,170 i think what are u exactly trying

to find

Step-by-step explanation:

NARA [144]2 years ago

8 0

Answer:

108

Step-by-step explanation:

So we can break this figure into 2 shapes. A rectangle and a right triangle.

Once we do that, we can solve the area for each shape.

Rectangle: 6 x 3 = 18

For the triangle, we'll need to find the sum of 6 + 6, which would be 12 to find the missing height for the triangle. Then we can find the area.

Triangle: (12 x 15)/2 = 90

We can then add our two answers up to get our final answer.

18 + 90 = 108

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mina [271]

Answer:

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Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

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$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

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