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3 years ago

I need help with this question

Mathematics

2 answers:

motikmotik3 years ago

8 0

Answer:1,170 i think what are u exactly trying

to find

Step-by-step explanation:

NARA [144]3 years ago

8 0

Answer:

108

Step-by-step explanation:

So we can break this figure into 2 shapes. A rectangle and a right triangle.

Once we do that, we can solve the area for each shape.

Rectangle: 6 x 3 = 18

For the triangle, we'll need to find the sum of 6 + 6, which would be 12 to find the missing height for the triangle. Then we can find the area.

Triangle: (12 x 15)/2 = 90

We can then add our two answers up to get our final answer.

18 + 90 = 108

You might be interested in

Determine which function has the greatest rate of change over the interval [0, 2].

ruslelena [56]

Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: $m= \frac{y_{2}-y_{1}}{x_2-x_1}$

Rate of change of $a$ :
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of $a$ :
$m= \frac{y_{2}-y_{1}}{x_2-x_1}$
$m= \frac{4-1}{2-0}$
$m= \frac{3}{2}$
$m=1.5$
The average rate of change of the function $a$ over the interval [0,2] is 1.5

Rate of change of $b$ :
Here the end points are (0,0) and (2,2)
$m= \frac{2-0}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $b$ over the interval [0,2] is 1

Rate of change of $c$ :
Here the end points are (0,-1) and (2,0)
$m= \frac{0-(-1)}{2-0}$
$m= \frac{1}{2}$
$m=0.5$
The average rate of change of the function $c$ over the interval [0,2] is 0.5

Rate of change of $d$ :
Here the end points are (0,0.5) and (2,2.5)
$m= \frac{2.5-0.5}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $d$ over the interval [0,2] is 1

We can conclude that the function that has the greatest rate of change over the interval [0, 2] is the function a.

4 0

3 years ago

Help!!!!!! Please I have no idea what this is!!!

Semmy [17]

Answer:

33.49 cubic units

Step-by-step explanation:

$V_{sphere} = \frac{4}{3} \times \pi {r}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi {(2)}^{3} \\ \\ V_{sphere} = \frac{4}{3} \times \pi \times 8 \\ \\ V_{sphere} = \frac{32 \times 3.14}{3} \\ \\ V_{sphere} = \frac{100.48}{3} \\ \\ V_{sphere} = 33.4933333\\ \\ V_{sphere} \approx 33.49\: units^3$

7 0

3 years ago

Safari isn’t helping so please help!!

Pepsi [2]

third option is the correct answer....

3 0

3 years ago

How do you simplify 2 15/10?

sdas [7]

First you take 15/10 and see that you can take 5 out of the top and bottom, so it would become 3/2. Now you have 2 3/2. 2 goes into 3 once with 1 remainder so 3/2= 1 1/2
So then you take the original 2 and add it to 1 1/2. The answer is now 3 1/2

6 0

3 years ago

Read 2 more answers

PLEASE HURRY :,) WILL GIVE BRAINLEST

Vlad1618 [11]

Answer:

Point R is at (-40,30), a distance of 60 units from point Q

Step-by-step explanation:

Explanation

we will use below conditions

Type of transformation change to co-ordinate point

vertical translation up 'd' units (x, y) changes to (x, y +d)
vertical translation down 'd' units (x, y) changes to (x, y-d)
horizontal translation left 'c' units (x, y) changes to (x- c, y)

4. horizontal translation right 'c' units (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

Now we have to find 'R' point

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is vertical translation up '60' units now changes the co-ordinate point is (-40 , -30+60)

The correct translation and The point R( -40 , 30)

Step2:-

Again in the given data "R" is at the same distance from point Q as point P is from point Q.

so given P point is (20 , -30)

now we translation 'P' also

vertically translation up at a distance '60' units and changes the new co-ordinate (20 , -30+60) that is (20,30) [ use above condition is (1)]

and again horizontal translation left '60' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

Final answer:-

Point R is at (−40, 30), a distance of 60 units from point Q

6 0

3 years ago