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2 years ago

I need help with this question

Mathematics

2 answers:

motikmotik2 years ago

8 0

Answer:1,170 i think what are u exactly trying

to find

Step-by-step explanation:

NARA [144]2 years ago

8 0

Answer:

108

Step-by-step explanation:

So we can break this figure into 2 shapes. A rectangle and a right triangle.

Once we do that, we can solve the area for each shape.

Rectangle: 6 x 3 = 18

For the triangle, we'll need to find the sum of 6 + 6, which would be 12 to find the missing height for the triangle. Then we can find the area.

Triangle: (12 x 15)/2 = 90

We can then add our two answers up to get our final answer.

18 + 90 = 108

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If the Probability of an event happening is 70%, what are the ODDS of the event happening?

elena55 [62]

Answer:

a) 7:10

Step-by-step explanation:

An example of this would be having seven blue marbles and three red marbles in a jar. If you randomly select one, the chance of that marble being blue is seventy, because 10 (total number of marbles) divided by seven (number of blue marbles) is 0.70, and if you convert this to a whole number (by multiplying it by 100) you get 70.

7 0

2 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

1 year ago

A three-dimensional array can be thought of as ______ of two-dimensional arrays.

Iteru [2.4K]

A page of two-dimensional arrays can be thought of as a three-dimensional array. Since 2-dimensional arrays are commonly expressed in tables or matrixes, therefore, if we put these tables or matrices in a page, the collection of matrices in a single page would now be structured into a 3D array.

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2 years ago

Please help ASAP. I really need this it is almost due. Please give me the right answer.

IceJOKER [234]

A and D
Put 3 in the equations and solve

5 0

2 years ago

The function h is defined by h (x) = 5x - 2.

Shtirlitz [24]

Answer:

x=2

Step-by-step explanation:

h(8)=5x-2

+2 +2

10=5x

Divide both sides by 5

x=2

5 0

2 years ago

Read 2 more answers