Answer:
please provide the diagram
Answer:
Given - Radius of ring is 9 millimeters
To find - Circumference
Solution -
9 millimeters = 0.9 centimeters
Circumference of circle = 2 × pie × r
= 2 × 3.14 × 0.9
= 6.28 × 0.9
= 5.652
I think it is 6/16 because if you add 1/4 with 5/12
Given AP is 21 ,18,15,...
First term = 21
Common difference = 18-21 = -3
Let an = -81
We know that
an = a+(n-1)d
⇛21+(n-1)(-3) = -81
⇛ 21-3n+3 = -81
⇛24-3n = -81
⇛ 24+81 = 3n
⇛ 105= 3n
⇛ n = 105/3
⇛ n = 35
35th term of the AP is -81.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> Which term of a AP 5 , 13 , 21 ,... is 181?
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Which term of the AP:3, 8, 13, 18,...,is 78?
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since T is the midpoint of SU, then ST = TU.
![\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B10x-14%7D%7B%5Cboxed%7BS%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20T%5Cstackrel%7B5x%2B16%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BU%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10x-14%7D%3D%5Cstackrel%7BTU%7D%7B5x%2B16%7D%5Cimplies%205x-14%3D16%5Cimplies%205x%3D30%5Cimplies%20x%3D%5Ccfrac%7B30%7D%7B5%7D%5Cimplies%20x%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10%286%29-14%5Cimplies%2046%7D~%5Chfill%20%5Cstackrel%7BTU%7D%7BTU%3DST%3D46%7D~%5Chfill%20%5Cstackrel%7BSU%7D%7BST%2BTU%3D92%7D)