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svet-max [94.6K]
3 years ago
5

Find the product. (2n + 2)(2n – 2)

Mathematics
2 answers:
antoniya [11.8K]3 years ago
7 0
Use the FOIL method, or (First, Outside, Inside, Last)

2n x 2n = 4n^2
2n x (-2) = -4n
2n x (2) = 4n
2 x (-2) = -4

4n² - 4n + 4n - 4   (simplify)

4n² (-4n + 4n) - 4

-4n + 4n = 0

4n² - 4 is your answer

hope this helps
vekshin13 years ago
3 0
<span>(2n + 2)(2n – 2)
= (2n)^2 -2^2
= 4n^2 - 4

hope it helps</span>
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A= [2, 3; 2, 1], B=[3; 5]. Find AB &amp; BA if possible
oksano4ka [1.4K]

Answer:

The value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right] and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right], B=\left[\begin{array}{ccc}3\\5\end{array}\right]

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2  and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]

AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]

AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]

AB=\left[\begin{array}{ccc}21\\11\end{array}\right]

Hence, the value of AB is \left[\begin{array}{ccc}21\\11\end{array}\right]

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1  and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

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the next "term", month will be 1.1 times more than the one before, namely r = 1.1, the common ratio.

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