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2 years ago

Solve the quadratic by quadratic formula below x squared-14x=-49

2 answers:

6 0

Equation ax²+bx+c=0 arrange the equation x²-14x+49=0 a=1 b=-14 c=49
General Formula= b+ or - √b²-4ac/2a by substituting gives us
-14+ or - √0/2 so we have one answer because 4ac is to b2 and √0 = 0 -14/2 = -7 The answer is one solution -7. If you want and extra hint there it is: b²-4ac is called the discriminant because it shows you how many solutions the equation will have if it's positive then it's 2 solutions and if it's zero then it's one solution and if it's negative no solution because b²-4ac is under a root and if a negative number is under a square root then it's undefined.

lubasha [3.4K]2 years ago

5 0

X^2-14x+49=0

Factor
(x-7)(x-7)

Check
-7-7=-14
-7*-7=49

Use ZPP
x-7=0
x=7

Final answer: x=7

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See the explanation

<h2>Explanation:</h2>

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3 years ago

Amy wants to sell at most 25 cookies and at least 10 sprites

Inga [223]

Answer:

$x\leq 25\\y\geq 10\\.50x + y\geq 30$

Step-by-step explanation:

It is given that,

Amy wants to sell at most 25 cookies ,

Let number of cookies be ' $x$ ' , then $x$ should be less than or equal to 25

Which is represented by $x\leq 25$ ,

Further,

Let number of sprites be ' $y$ ', then ' $y$ ' should be greater than or equal to 10

Which is represented by $y\geq 10$

Also,

Given,

she profits $.50 on every cookie

and $1.00 on every sprite.

So total profit on selling cookies would be

= Profit on each cookie times the number of cookies

= $.50\times x$

= $.5x$

Similarly, total profit on selling sprites would be

=profit on each sprite times the number of sprites

= $1.00\times y$

= $y$

Now, combining these two should be greater than or equal to $30

representing this through an equation,

$.50x+y\geq 30$

Thus the sysytem of equations is given as:

$x\leq 25\\y\geq 10\\.50x + y\geq 30$

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2 years ago

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Answer:

Step-by-step explanation:

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