A^-b = 1/a^b
a^b / a^c = a^b-c
a^c / b^c =(a/b)^c
Number 21 would be 6 39/40
Answer:
(A) Complements of the same angle are congruent.
Step-by-step explanation:
Since, ∠CEF is complementary to ∠DCF, therefore
∠CEF+∠DCF=90° (1)
Also, ∠CEG=∠CEF+∠FEG
⇒90°=∠CEF+∠FEG (2)
Therefore, from(1) and (2), we get
∠CEF+∠DCF=90°
∠CEF+∠FEG=90°
Subtracting both the equations, we get
∠DCF-∠FEG=0
∠DCF=∠FEG.
Hence, ∠DCF≅∠FEG by the rule: Complements of the same angle are congruent.
Ahh this is a good hard question, hopefully someone comes along and helps you out with it. Goodluck my friend!