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gregori [183]
3 years ago
12

Solve 5(x-1)^1/3 = 20

Mathematics
1 answer:
dangina [55]3 years ago
8 0

Answer:

x = 65

Step-by-step explanation:

To solve the equation, we write it in radical form:

5\, \sqrt[3]{x-1} = 20

Then, we divide both sides by 5 to isolate the root:

\sqrt[3]{x-1} = \frac{20}{5} \\\sqrt[3]{x-1} =4

and next, we raise both sides of the equation to the power 3 so as to free the expression in x from the root:

x-1=4^3\\x-1=64

now we add 1 to both sides to isolate x:

x = 65

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Hey there!


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So, 12 would most likely be number before you make your parentheses


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The numbers in your original equation both share 3 & -1


So, therefore the factor form of your equation should be: 12(3y - 1)


Answer: 12(3y - 1)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

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