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andre [41]
2 years ago
14

Can someone help me pls

Mathematics
2 answers:
notsponge [240]2 years ago
4 0

Answer:

64

Step-by-step explanation:

Natalka [10]2 years ago
4 0

Answer:

64 Is the answer easy

Step-by-step explanation:

64 is the answer

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Find the missing angle measurements for each problem below and drag the answers into the correct blanks.
jeyben [28]

Step-by-step explanation:

4)180-57.8=123.3

5)180-116.4=64.6

4 0
2 years ago
8z=4(2z+1) show step by step
Verizon [17]
8z=4(2z+1)
First you would distribute the constant into the numbers in the parentheses. so
8z=8z+4
then you would combine like terms which in this case would result in a zero.
8z-8z=0 So the z would be zero or no solution.
5 0
3 years ago
Find the inverse of square root f(n) = n – 3.
pogonyaev

Answer:

f'(n) = n + 3

Step-by-step explanation:

Given

f(n) = n - 3

Required

The inverse

f(n) = n - 3

Replace f(n) with y

y = n - 3

Swap positions of y and n

n = y - 3

Make y the subject

y = n + 3

Replace y with f'(n)

f'(n) = n + 3

4 0
3 years ago
Solve and round answer to nearest hundredth please.
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

Solve this by using natural logs.  Taking the natural log of both sides:

ln(7*16^{8x-8})=ln(3)

To undo the multiplication, we use addition:

ln(7)+ln(16)^{8x-8}=ln(3)

The rule says we can now bring the exponent down in front of the ln:

ln(7)+(8x-8)ln(16)=ln(3)

Now we will subtract ln(7) from both sides:

(8x - 8)ln(16) = ln(3) - ln(7)

Now we will divide both sides by ln(16):

8x-8=\frac{ln(3)-ln(7)}{ln(16)} then add 8 to both sides:

8x=\frac{ln(3)-ln(7)}{ln(16)}+8 which simplifies to

8x = 7.694401895 so

x = .9618002368 or, rounded,

x = .96

(Rest assured I did the math and checked the answer and it checked out perfectly!)  I recommend you learn the laws of natural and common logs cuz they're kinda important!! :)

5 0
3 years ago
Pls help this is due soon check 2 that apply
dem82 [27]

Answer:

I am pretty sure it is option a and c

Sorry if i am wrong

3 0
3 years ago
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