PQ is tangent to the circle at C. In the circle, In the circle, Arc mBC=89. Find mBCP.
1 answer:
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Answer:
sin A = 15/17
sec A = 17/8
Step-by-step explanation:
15 cot A = 8
First get cot A alone.
cot A = 8 / 15
Since cot is the reciprocal of tan then flip 15 and 8.
tan A = 15 / 8
Now you have the opposite and adjacent sides, just find the hypotenuse with Pythagorean's theorem
15^2 + 8^2 = 289
= 17
Now that you have all the sides use the opposite and hypotenuse to get sine and the adjacent and hypotenuse to get cosine then flip to get secant.
sin A = 15/17
cos A = 8/17
sec A = 17/8
Answer:
1. Julie’s scenario doesn't match the linear function graphed, because the graphed function is f(x)=-3x+12 and must be f(x)=-5x+12
2. She has counted the slope of the line incorrect.
3. She can write f(x)=-5x+12 and draw the line with the x-intercept will be at (2.4,0) and y-intercpt ar (0,12).
Step-by-step explanation:
If Joe parked 12 miles away from the cabin and after one hour, he was still 7 miles from the cabin, then he had walked 12 - 7 = 5 miles per hour.
The initial positon of Joe is at point (0,12) (after 0 hours passed, Joe was 12 miles from the cabin). The line must pas through the point (1,7) ( after one hour, he was still 7 miles from the cabin ).
Find the slope:
So, the slope of the linear function should be -5 (not -3).
Then the equation of the function is
1. Julie’s scenario doesn't match the linear function graphed, because the graphed function is f(x)=-3x+12 and must be f(x)=-5x+12
2. She has counted the slope of the line incorrect.
3. She can write f(x)=-5x+12 and draw the line with the x-intercept will be at (2.4,0) and y-intercpt ar (0,12).