Choose all the possible solution that makes the inequality statement True

Mathematics

1 answer:

Verizon [17]3 years ago

4 0

Answer:

18, 19, 20

-18,-19,-20

Step-by-step explanation:

x + 15 ≤ 35

x ≤ 35 - 15

x ≤ 20

x must be 20 or less than it

You might be interested in

A box of books has a mass of 4.10 kilogram for ever meter of its height a box of magazines has a mass of 3 pounds for every foot

Tju [1.3M]

No rounding is necessary to answer the question.

We can subtract the (linear) density of the second box from that of the first to see which box is heavier per unit height.

$\dfrac{4.10\,kg}{1\,m}-\dfrac{3\,lb}{1\,ft}=\dfrac{4.10\,kg}{1\,m}\cdot\dfrac{1\,lb}{0.45\,kg}-\dfrac{3\,lb}{1\,ft}\cdot\dfrac{3.28\,ft}{1\,m}\\\\=\dfrac{4.10\,lb}{0.45\,m}-\dfrac{3\cdot 3.28\,lb}{1\,m}=\dfrac{4.10-3\cdot 3.28\cdot 0.45}{0.45}\dfrac{lb}{m}=\dfrac{4.10-4.428}{0.45}\dfrac{lb}{m}$

This value is obviously less than zero, so ...

... the box of magazines has the greater mass per unit height.

_____

The question didn't ask for the mass per height, and we didn't compute it. All we did was make a conversion to comparable units. The units we ended up with are mixed English and metric units, but that doesn't matter for the purpose of comparison.

Since all we're really interested in is <em>the sign of the difference</em> of mass/height, we don't even need to actually compute that difference. We just need to do enough computation to be able to tell whether the sign is positive or negative.

3 0

4 years ago

What is 0.3111111111111111 as a fraction?

Citrus2011 [14]

$\sf~N=0.3\overline{1}$

There is only one repeating number, so we multiply both sides by $\sf10^1$ or $\sf10$ .

$\sf10N=3.\overline{1}$

Now subtract the original number we had to both sides, which is the same as $\sf~1N$ or $\sf~N$

So we have:

$\sf9N=2.8$

Divide 9 to both sides:

$\sf~N=\dfrac{2.8}{9}$

Multiply the fraction by 10 to get rid of the decimal in the numerator.

$\sf~N=\dfrac{28}{90}$

Simplify the fraction by dividing the numerator and denominator by 2:

$\sf~N=\boxed{\sf\dfrac{14}{45}}$