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professor190 [17]
3 years ago
9

How can you use a function to represent a linear relationship?

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

A linear relationship is a relationship with a constant rate of change represented by a graph that forms a straight line that passes through the origin (0, 0) and is represented by y = kx. The rate of change is either positive, negative, zero, or undefined.

Step-by-step explanation:

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each hour the number of bacteria in dr. nall's petri dish tripled what percent is the population compared to the population the
yan [13]
The starting percent is 100%. After one hour, bacteria tripled, so it is 300%.
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Find the difference <br> (6ab+4a-3) - (2ab-4)
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This would be 8(ab) sooo yaaaa
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Graph the line perpendicular to x = -2 that passes through ( -3, 7)
erma4kov [3.2K]

Answer:

The parallel line would be y = 7

Step-by-step explanation:

If a line is parallel to x = -2, then it is a horizontal line. All horizontal lines can be written in the form of y = (a number). That number can be found as the y-coordinate in the ordered pair given.

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8 0
3 years ago
Find a and b such that gcd(a, b) = 14, a &gt; 2000, b &gt; 2000, and the only prime divisors of a and b are 2 and 7.
choli [55]

Answer:

a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

a = 2^\alpha.14 \\b = 7^\delta.14

All we have left to do is find the possible values for \alpha and \delta so that a>2000 \ , b>2000 and that only happens if \alpha\geq 8 and \delta\geq 3

8 0
4 years ago
What is the volume of the rectangular prism <br>30ft3 <br>224ft3<br>576ft3<br>896ft3
GREYUIT [131]

just multiply the values

8×8×14= 896ft³

6 0
4 years ago
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