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Natalija [7]
2 years ago
5

(HELP!!!) Please Factor Completely: 9x^2y^2-27x^2y-72y^2+216y

Mathematics
1 answer:
Olegator [25]2 years ago
4 0

Answer:

Can u space them out so i know which ones are exponents

Step-by-step explanation:

You might be interested in
A banks loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviati
Alona [7]

Answer:

2.87%

Step-by-step explanation:

We have the following information:

mean (m) = 200

standard deviation (sd) = 50

sample size = n = 40

the probability that their mean is above 21.5 is determined as follows:

P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]

P (x> 21.5) = P (z> -22.57)

this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:

P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]

P (x> 215) = P (z> 1.897)

P (x> 215) = 1 - P (z <1.897)

We look for this value in the attached table of z and we have to:

P (x> 215) = 1 - 0.9713 (attached table)

P (x> 215) =.0287

Therefore the probability is approximately 2.87%

4 0
3 years ago
Write the slope-intercept form of the equation of the line through the given point with the given slope. through: (1, 1), slope
RSB [31]

Answer:

y=2x-1

Step-by-step explanation:

y-y1=m(x-x1)

y-1=2(x-1)

y=2x-2+1

y=2x-1

Please mark me as Brainliest if you're satisfied with the answer.

7 0
2 years ago
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Find the surface area of the figure below.
bulgar [2K]
To find the surface area we deconstruct the figure then add all the areas together.

The area of the rectangle on the bottom is 8*6 or 48.
The side rectangles are 5*6 or 30. 
The two triangles are \frac{8*3}{2} or 12.

48+30+30+12+12= 132.

Hope this helps!


6 0
3 years ago
The length of a rectangle is 10 meters more than the width. if the perimeter is 52 meters, find the length and width
Ray Of Light [21]
P = 2(L + W)
P = 52
L = W + 10

52 = 2(W + 10 + W)
52 = 2(2W + 10)
52 = 4W + 20
52 - 20 = 4W
32 = 4W
32/4 = W
8 = W <==== the width is 8 meters

L = W + 10
L = 8 + 10
L = 18 <==== the length is 18 meters
4 0
3 years ago
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