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mariarad [96]
3 years ago
9

Need help please...............................

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0
Note that the side adjacent to angle XYZ is given (6 cm) and that the hypo is also given (15 cm).  Thus, cos XYZ = adj / hyp = 6 cm / 15 cm  = 2/5 = 0.4.

XYZ is then  arc cos 0.4.  Use the arccos function on your calculator to determine XYZ and give XYZ in both degrees and radians.
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Plsss help will mark brainliest
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C, because 7 divided, or over nine, is 7/9
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A recipe calls for the following spices: 18 teaspoon of turmeric, 18 teaspoon of ginger, and 14 teaspoon of cumin. What is the t
Sphinxa [80]

Answer:

50 total

Step-by-step explanation:

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How to do graphs of quadratic functions ​
Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0
2 years ago
Can I get your opinion on if this looks right and if not, how should it be done?
mrs_skeptik [129]
It looks good to me!!
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3 years ago
Evaluate the expression: 81 / 9 + (5 with the exponet of 2- 6.7) - 12
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