Ask question

Ask question

All categories

3 years ago

5

Find the midpoint of a line segment whose endpoints are (7, 6) and (2, 3).

1 answer:

Lelu [443]3 years ago

5 0

Answer:

(9/2, 9/2)

Step-by-step explanation:

midpoint formula = (x1 + x2/2, y1 + y2/2)

(7,6) is x1 and y1.

(2,3) is x2 and y2.

Solve:

x-coordinate= (7+2)/2 = 9/2 or 4.5

y-coordinate= (6+3)/2 = 9/2 or 4.5

your final answer is (9/2, 9/2)

decimal form = (4.5, 4.5)

You might be interested in

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

Q1:

$-5\sqrt{27c^2}$

$-5\sqrt{27}\sqrt{c^2}$

$-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}$

$-5\times3\sqrt{3}\sqrt{c^2}$

$-5\times3\sqrt{3}c$

$-15\sqrt{3}c$

Q2:

$5\sqrt{72}-3\sqrt{32}$

$5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}$

$5\times6\sqrt{2}-3\times4\sqrt{2}$

$30\sqrt{2}-12\sqrt{2}$

$18\sqrt{2}$

Q3:

$\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}$

$\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}$

$6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}$

$16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}$

Q4:

$\sqrt{15n^2}\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}$

$\sqrt{15}\sqrt{10}n^2\sqrt{n}$

$\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{3}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{6}n^2\sqrt{n}$

Q5:

$\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}$

$\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}$

Cancel off $\sqrt{x}$ :

$\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}$

Cancel off $y:$

$\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}$

Cancel off $\sqrt{y} :$

$\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}$

Multiply $\sqrt{5}$ on the numerator and denominator:

$\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}$

$\frac{\sqrt{15}\sqrt{x}}{20}$

5 0

3 years ago

Helppppppp pleaseeeeeee

pshichka [43]

Answer:

(2a, 2b)

Step-by-step explanation:

(0, 2b)

(2a, 0)

(2a, 2b)

I racked my brain for that.

4 0

3 years ago

Water is flowing at the rate of 15 km/hr through a pipe of diameter 14 cm into a cuboidal pond

tatyana61 [14]

2 hours.

hope this helped

7 0

3 years ago

NISA [10]

Answer:

$r = 0.01$

Step-by-step explanation:

In order to find r we have to square both sides of the equation

$0.1 = \sqrt{r} \\ {0.1}^{2} = { \sqrt{r} }^{2}$

The *square root* sign cancels out the *squared* sign therefore:

${0.1}^{2} = r \\ 0.01 = r$

6 0

2 years ago

Which systems of equations intersect at point A in this graph?

Svet_ta [14]

Y = 4 x - 9

y = - 3 x - 5

I hope this will help you

i looked this up and this is what i got

6 0

3 years ago