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dmitriy555 [2]
3 years ago
10

Graph the line. 2x + y = -4 I need the first 2 points to plot

Mathematics
2 answers:
Finger [1]3 years ago
7 0

Answer:

(0,-4)

(1,-6)

Step-by-step explanation:

2x+y = -4

y = -2x - 4

f(x) = -2x -4

either use the table function on a standar fx-991ES Plus calculator, or just substitute values of x to get the values for the y co-ordinate,

where x = -1

y = -2(-1) -4

y = -2

hence at x = -1, y = -2 . co-ordinates = (-1,-2)

and starting at -1 , doing this for numbers till 3 we get

(-1,-2)

(0,-4)

(1,-6)

MAVERICK [17]3 years ago
3 0

Answer:

-1, -2

0,-4

1,-6

Step-by-step explanation:

did it

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3 years ago
78 divided by 190 <br><br>steps
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78 x 100 = 7800 

<span>How many times does 190 go into 780? </span>
<span>≈ 4....190 x 4 = 760 </span>

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5 0
3 years ago
A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

7 0
3 years ago
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