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Ede4ka [16]
2 years ago
10

8 ft Find the area of the figure.

Mathematics
1 answer:
lina2011 [118]2 years ago
5 0

Answer:

Area of a rectangle is length multiplied by the width. In this case, length is equal to width. So, Area is 8 ft * 8 ft which is 64 ft2.

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For the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B5%7D%20%2B2" id="TexFormula1" title="\f
Ber [7]

Answer:

f^{-1}(x)=25(x-2)^2

Step-by-step explanation:

The inverse function can be found by solving ...

  f(y) = x

  (√y)/5 +2 = x

  (√y)/5 = x -2 . . . . . subtract 2

  √y = 5(x -2) . . . . . . multiply by 5

  y = 25(x -2)² . . . . . square both sides

The inverse function is ...

  f^{-1}(x)=25(x-2)^2

_____

<em>About the graph</em>

The inverse of a function is its mirror image across the line y = x.

4 0
3 years ago
At the craft store, Ayana bought a bag of blue and orange marbles. She received 41 blue marbles and 9 orange marbles. What perce
RoseWind [281]

Answer:

82%

Step-by-step explanation:

41+9 is 50(total marbles)

41/50 (blue/total) is 82%! :)

5 0
2 years ago
Read 2 more answers
Evaluate the expression
ohaa [14]

Answer:

  10

Step-by-step explanation:

\dfrac{5\cdot x^3}{x^2}=5x

For x=2, this is ...

  5·2 = 10

7 0
3 years ago
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Can you help me please?
ExtremeBDS [4]

Answer:

0≤x≤8

Step-by-step explanation:

the domain is basically all the x-values that are applicable to the graph.

Here we can clearly see that the graph starts at x = 0 and ends at x = 8. There are no other possible x-values which is applicable to the graph,

hence the domain is 0≤x≤8

6 0
3 years ago
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If ln(4x+y)=2x-3,then dy/dx=
Viktor [21]

\ln(4x+y)=2x-3

Differentiate both sides wrt x:

\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}

4 0
3 years ago
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