Answer: The answer is 139 feet
H = height of the pole =?
BC = ED = height of the transit = 4 ft
CD = BE = distance moved away from the base of the pole = 140 ft
Consider the ΔABE
tan44 = AE/BE
tan44 = h/140
h = 140 tan44
h = 135.2 ft
H = height of pole = AE + ED = h + ED = 135.2 + 4
H = 139.2 ft
Step-by-step explanation:
I think it’s gonna be the 3rd one
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
