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bearhunter [10]
3 years ago
14

Students at a local high school are given the option to take one gym class, one music class or one of each. Out of 100 students,

60 say that they are currently taking a gym class and 70 say that they are taking a music class. How many students are taking both ?
Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

I might be wrong but I think it's 30

Step-by-step explanation:

60+70=130

130-100=30

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Consider the equation y=-2x+5. Create a table of five ordered pairs that satify the equation. What is the slope of the line repr
tekilochka [14]
Here are 5 ordered pairs (0,5) (1,3) (2,1) (3, -1) (4, -3)
The slope is -2 of c. You always call the y intercept b and the slope m.
4 0
3 years ago
Read 2 more answers
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
Please help thanks !!
Amanda [17]

Answer:

Roughly 3.02 times greater

Step-by-step explanation:

2720546/900000 = 3.022_  ( the underscore means the numbers go on. )

8 0
2 years ago
What is the answer of the following question. ​
statuscvo [17]

Answer:

can you turn it around i cant see it

Step-by-step explanation:

7 0
2 years ago
A 20-foot piece of wire is attached from the top of a flagpole to a stake in the ground 8 feet from the base of the pole. Find t
Dovator [93]

Answer:

18.33

Step-by-step explanation:

a²+b²=c²

a²+8²=20²

a²+64=400

subract 64 from both sides

a²=336

\sqrt{336}=18.33

6 0
3 years ago
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