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bearhunter [10]
3 years ago
14

Students at a local high school are given the option to take one gym class, one music class or one of each. Out of 100 students,

60 say that they are currently taking a gym class and 70 say that they are taking a music class. How many students are taking both ?
Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

I might be wrong but I think it's 30

Step-by-step explanation:

60+70=130

130-100=30

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Step-by-step explanation:

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a local hamburger shop sold a combined total of 616 hamburgers and cheeseburgers on sunday. there were 66 moore cheeseburgers so
Ksju [112]

Answer:

242 Hamburgers,  374 Cheeseburgers

Step-by-step explanation:

Step 1: 616/2-66=242 Hamburgers

Step 2: 616-242=374 Cheeseburgers

Step 3: Check Work 242+374=616

4 0
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Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle Q? You must show all work and calcu
viktelen [127]
Hello,

Angles y and 3y+8 are supplementaries since the quadrilater is inscribed

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8 0
3 years ago
What is 2/3 divided by 3/4
ad-work [718]

Answer:

8/9

Step-by-step explanation:

It can sometimes be difficult to divide fractions, such as 2/3 divided by 3/4! When we divide two fractions, such as 2/3 ÷ 3/4, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other. We also simplify the answers to fraction problems whenever possible.

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8 0
2 years ago
Two machines are used for filling plastic bottles to a net volume of 16.0 ounces. A member of the quality engineering staff susp
aleksandrvk [35]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if the two machines are filling the bottles with a net volume of 16.0 ounces or if at least one of them is different.

The parameter of interest is μ₁ - μ₂, if both machines are filling the same net volume this difference will be zero, if not it will be different.

You have one sample of ten bottles filled by each machine and the net volume of the bottles are measured, determining two variables of interest:

Sample 1 - Machine 1

X₁: Net volume of a plastic bottle filled by the machine 1.

n₁= 10

X[bar]₁= 16.02

S₁= 0.03

Sample 2 - Machine 2

X₂: Net volume of a plastic bottle filled by the machine 2

n₂= 10

X[bar]₂= 16.01

S₂= 0.03

With p-values 0.4209 (for X₁) and 0.6174 (for X₂) for the normality test and using α: 0.05, we can say that both variables of interest have a normal distribution:

X₁~N(μ₁;δ₁²)

X₂~N(μ₂;δ₂²)

Both population variances are unknown you have to conduct a homogeneity of variances test to see if they are equal (if they are you can conduct a pooled t-test) or different (if the variances are different you have to use the Welche's t-test)

H₀: δ₁²/δ₂²=1

H₁: δ₁²/δ₂²≠1

α: 0.05

F= \frac{S^2_1}{S^2_2} * \frac{Sigma^2_1}{Sigma^2_2} ~~F_{n_1-1;n_2-1}

Using a statistic software I've calculated the test

F_{H_0}= 1.41

p-value 0.6168

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis then you can conclude that both population variances for the net volume filled in the plastic bottles by machines 1 and 2 are equal.

To study the difference between the population means you can use

t= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }  ~~t_{n_1+n_2-2}

The hypotheses of interest are:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

Sa= \sqrt{\frac{(n_1-1)S^2_1+(N_2-1)S^2_2}{n_1+n_2-2}} = \sqrt{\frac{9*9.2*10^{-4}+9*6.5*10^{-4}}{10+10-2} } = 0.028= 0.03

t_{H_0}= \frac{(16.02-16.01)-0}{0.03*\sqrt{\frac{1}{10} +\frac{1}{10} } } = 0.149= 0.15

The p-value for this test is: 0.882433

The p-value is greater than the significance level, the decision is to not reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to reject the null hypothesis. You can conclude that the population average of the net volume of the plastic bottles filled by machine one and by machine 2 are equal.

I hope this helps!

8 0
3 years ago
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