Question

A shelf is designed so it will fit in a 90º corner between two walls. The shelf has dimensions, rounded to the nearest tenth, as shown. A triangle has side lengths 11 centimeters, 11 centimeters, and hypotenuse of StartRoot 242 EndRoot centimeters. [Not drawn to scale] Will the shelf fit snugly in a 90º corner?

Answer 1

Answer:

Yes, it will fit snugly in a 90º corner

Step-by-step explanation:

To do this, we simply need to check if the given sides of the shelf is right-angled.

So, we have:

$Hypotenuse = \sqrt{242$

$Side\ 1 = Side\ 2 = 11$

To check for right-angle triangle, we make use of:

$Side\ 1^2 + Side\ 2^2 = Hypotenuse^2$

This gives:

$11^2 + 11^2 = \sqrt{242}^2$

$121 + 121 = \sqrt{242}^2$

$242 = \sqrt{242}^2$

$242 = 242$

This shows that the given sides of the shelf is a right-angled triangle.

Hence, it will fit the wall