Answer:
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
Step-by-step explanation:
x = Number of hockey games Infotron should produce
y = Number of soccer games Infotron should produce
Number of labor-hours for assembly = 2x + 3y
Number of labor-hours for testing = 2x + y
Now we can write our equations system, this way:
2x + 3y = 44
2x + y = 32
*********************
Expressing y in terms of x in the 2nd equation:
2x + y = 32
y = 32 - 2x
********************
Substituting y and solving for x in the 1st equation:
2x + 3y = 44
2x + 3 * ( 32 - 2x) = 44
2x + 96 - 6x = 44
-4x = 44 - 96
-4x = - 52
x = -52/-4
x = 13
*****************
Solving for y in the 2nd equation:
2x + y = 32
2 * 13 + y = 32
26 + y = 32
y = 32 - 26
y =<u> 6</u>
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
You add 9 to both sides to get:
<span>y – 9 + 9 = –17 + 9
</span>
so it's <span>Addition Property of Equality
answer
</span>B.Addition Property of Equality
Answer:
0.7102
0.8943
0.3696
Step - by - Step Explanation :
A.) Between $1320 and $970
P(Z < 1300) - P(Z < 970)
find the Zscore of each scores and their corresponding probability uinag the standard distribution table :
P(Z < (x - μ) /σ) - P(Z < (x - μ) / σ))
P(Z < (1320 - 1250) /120) - P(Z < (970 - 1250) / 120))
P(Z < 0.5833) - P(Z < - 2.333)
0.7200 - 0.0098 = 0.7102 (Standard
=0.7102
B.)Under 1400
x = 1400
P(Z < 400)
P(Z < (x - μ) /σ)
P(Z < (1400 - 1250) /120)
P(Z < 1.25) = 0.8943
C.) Over 1290
P(Z > 1290)
P(Z < (x - μ) /σ)
P(Z > (1290 - 1250) /120 = 0.3333
P(Z > z) = 1 - P(Z < 0.3333) = P(Z < 0.3333) = 0.6304
P(Z > 0.3333) = 1 - 0.6304 = 0.3696
