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dolphi86 [110]
3 years ago
11

In a one-month period, a convenience store

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0
So, youd start by adding the two sales together to get total sales. Then you would divide that number by the gas sales to get the percent

65560+36740 = x

36740/ x = the percentage :)
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When a number is increased by 40 % it gives 84. Find the original number
Julli [10]
I believe the answer is $33.60?
3 0
3 years ago
Read 2 more answers
What two numbers add to make twenty and have a difference of four?
lara [203]
The two numbers that add to make twenty and have a difference of 4 are 12 and 8
4 0
4 years ago
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W + 3 = 5z ; solve for w<br> ——— <br> 4
AveGali [126]

Answer:

all work is pictured and shown

8 0
3 years ago
Triangle A C B is cut by line segment E D. Line segment E D goes from side B C to side A C. The length of B A is 4 x minus 6 and
bezimeni [28]

From the markings on the diagram, we can tell E is the midpoint of BC and <u>D</u> is the midpoint of AC. We can apply the <u>triangle midsegment theorem</u>: ED = ½BA. Substituting in the expressions for the lengths and solving for x, we get x = <u>5</u>. Now, since BE = x, then BC = <u>10</u>.

<h3>What is triangle midpoint theorem?</h3>

Triangle midpoint theorem states that the line segment which joins the midpoints of two (2) sides of a triangle is parallel to the third side, and it's congruent to one-half of the third side.

By applying the triangle midpoint theorem, we can find the value of x:

ED = ½BA

x + 2 = ½(4x - 6)

2x + 4 = 4x - 6

4x - 2x = 6 + 4

2x = 10

x = 10/2

x = 5.

BC = x + x

BC = 5 + 5

BC = 10.

Read more on triangle midpoint theorem here: brainly.com/question/16047906

#SPJ1

6 0
2 years ago
Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el
sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

= 30/100 \ of \ x\\= 0.3x

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

= 106.48-79.86\\= 26.62

3 0
3 years ago
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