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ipn [44]
3 years ago
8

Question one please!

Chemistry
1 answer:
enot [183]3 years ago
8 0

Answer:

a      

Explanation:

You might be interested in
¿Quién estableció el concepto moderno de elemento?
Zina [86]

Answer:

Robert Boyle

Explanation:

En muchos textos se suele considerar a Robert Boyle como el científico que introdujo en la Química un concepto de elemento diferente al empleado por los aristotélicos o por los alquimistas y que sirvió de antecedente al que formulara Lavoisier en 1789.

7 0
3 years ago
How many moles of iron in a sample that contains 7.91×10^23 atoms of iron?
vazorg [7]

Answer: 1.31

Explanation:  

No.of moles = given no.of atoms/Avagadro number

= 7.91×10^23 / 6.022 x 10^23

= 1.31

therefore, no.of moles = 1.31

Hope it helped u,

pls mark as the brainliest

^_^

5 0
3 years ago
What is the molarity of a solution that contains 15.0g of naoh per 500.0 ml of solution ​
VARVARA [1.3K]

Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,  

NaOH

, divided by liters of solution.

molarity

=

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,  

mL

.

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

7

g

⋅

1 mole NaOH

40.0

g

=

0.175 moles NaOH

The volume of the solution in liters will be

500

mL

⋅

1 L

1000

mL

=

0.5 L

Therefore, the molarity of the solution will be

c

=

n

V

c

=

0.175 moles

0.5 L

=

0.35 M

Rounded to one sig fig, the answer will be

c

=

0.4 M

8 0
3 years ago
Calculate the percent composition by mass of oxygen in HClO
r-ruslan [8.4K]

Answer:

percentage composition of O in HClO IS 30.47

Explanation:

percentage composition of oxygen in HClO =(atomic mass of O)/(atomic mass of HClO)×100

               =\frac{16}{1+35.5+16}\times 100

                =30.47

4 0
3 years ago
1. What is the molarity of 6.4g of methanol dissolved in 50 moles of water2. If the density of the above solution at 25C is 1.03
ICE Princess25 [194]

Answer:

1. 0.22 mol/dm³

2. 0.23 mol/dm³

Explanation:

Molarity: This can be defined as the concentration of a substance  in mol per dm³

1.

M = n/v ...................... Equation 1

M = molarity of methanol, n = number of mole of methanol, v = volume of the solvent/water/solution.

<em>n = g/m.m</em>

<em>Where g = mass of methanol, m.m = molar mass of methanol.</em>

<em>g = 6.4 g, m.m = 32 g /mole.</em>

<em>n = 6.4/32 = 0.2 mole</em>

<em>and ,</em>

<em>v = m/d </em>

<em>Where m = mass of water, d = density of water</em>

<em>m = mass of 50 moles of water = 18×50 = 900 g.</em>

d = 1000 g/dm³.

v = 900/1000 = 0.9 dm³

Substituting the value of v and n into equation 1

M = 0.2/0.9

M = 0.22 mol/dm³

2.

M = n/v

v = volume of the solution

v = (mass of methanol + mass of water in the solution)/density of the solution

v = [(900+6.4)/1000]/1.03

v = 0.9064/1.03

v = 0.88 dm³

n = 0.2 mole

Therefore,

M = 0.2/0.88

M = 0.23 mol/dm³

3 0
3 years ago
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