Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
8 1/2 would be the answer to this question
First oy ufind the hieth ande the width then you multiply them and add the othersa with addition
Perform the indicated division ... divide the numerator by the denominator.
The quotient is the decimal form of the ratio.
Answer:
27.37 and 9.18
Step-by-step explanation:
(4)
Using the cosine ratio in the right triangle
cos64° = 
= 
( multiply both sides by x )
x × cos64° = 12 ( divide both sides by cos64° )
x = 
≈ 27.37 ( to the nearest hundredth )
(5)
Using the sine ratio in the right triangle
sin35° = 
= 
( multiply both sides by 16 )
16 × sin35° = x , then
x ≈ 9.18 ( to the nearest hundredth )
