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VMariaS [17]
3 years ago
11

Is y=1-x to the second power linear or nonlinear

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

Non Linear

Step-by-step explanation:

Its non-linear because when you put X to the second power, it will change the function into a quadratic function

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In 1990, 75% of all high school seniors had jobs. In 2010, 40% of all seniors had jobs. If there were 50 more seniors in 2010 th
Maru [420]

Answer:

There were 333 seniors in 1990

153 seniors had jobs in 2010.

Step-by-step explanation:

Let the number of high school seniors in 1990 = x

75% of x had jobs in 1990

In 2010 there were 50 more seniors. That is, the number of seniors is x+50.

40% of (x+50) had jobs in 2010.

Total number of jobs in both years = 403.

\[0.75 * x + 0.4 * (x + 50) = 403\]

\[0.75 * x + 0.4 * x  + 20 = 403\]

=> \[1.15 * x  = 403 - 20\]

=> \[1.15 * x  = 383\]

=> \[x  = 383/1.15\]

=> \[x  = 333\]

Number of seniors having job in 2010 = 0.4 * (333 + 50) = 0.4 * 383 = 153.2 = 153(approx)

7 0
3 years ago
Find the area of the shaded region
SOVA2 [1]

We know that, Area of a Circle is given by : πR²

Where : R is the Radius of the Circle.

We can Notice that : The Given Figure is One - Fourth of the Circle with Radius 'R'

\mathsf{\implies Area\;of\;One\;Quarter\;of\;the\;Circle = \frac{\pi R^2}{4}}

We can Notice that : The Quarter of the Circle is divided into 3 Equal Parts and The Shaded Region is One of the Equal Part.

\mathsf{\implies Area\;of\;Shaded\;Region = \frac{\frac{\pi R^2}{4}}{3}}

\mathsf{\implies Area\;of\;Shaded\;Region = {\frac{\pi R^2}{12}}}

3 0
3 years ago
Read 2 more answers
What is 17/15 as a mixed number and 2 31/18
inna [77]
17/15 as a mixed number is 1 2/15. 2 31/18 as a mixed number is 54 13/18.
6 0
3 years ago
Which of the following is a step in constructing a circle circumscribed about a triangle?
MatroZZZ [7]
I think it is the last one
5 0
3 years ago
Two bumper cars are driven straight toward
Evgen [1.6K]

By conservation of momentum,

(110.0 kg) (1.5 ms⁻¹) + (170.0 kg) (-2.0 ms⁻¹) = (110.0 kg) (-2.75 ms⁻¹) + (170.0 kg) v

where v is the final velocity of the second car.

Solve for v :

-175 kg•ms⁻¹ = -302.5 kg•ms⁻¹ + (170.0 kg) v

127.5 kg•ms⁻¹ = (170.0 kg) v

v = (127.5 kg•ms⁻¹) / (170.0 kg) = 0.75 ms⁻¹

5 0
3 years ago
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