Answer:
There were 333 seniors in 1990
153 seniors had jobs in 2010.
Step-by-step explanation:
Let the number of high school seniors in 1990 = x
75% of x had jobs in 1990
In 2010 there were 50 more seniors. That is, the number of seniors is x+50.
40% of (x+50) had jobs in 2010.
Total number of jobs in both years = 403.
\[0.75 * x + 0.4 * (x + 50) = 403\]
\[0.75 * x + 0.4 * x + 20 = 403\]
=> \[1.15 * x = 403 - 20\]
=> \[1.15 * x = 383\]
=> \[x = 383/1.15\]
=> \[x = 333\]
Number of seniors having job in 2010 = 0.4 * (333 + 50) = 0.4 * 383 = 153.2 = 153(approx)
We know that, Area of a Circle is given by : πR²
Where : R is the Radius of the Circle.
We can Notice that : The Given Figure is One - Fourth of the Circle with Radius 'R'
We can Notice that : The Quarter of the Circle is divided into 3 Equal Parts and The Shaded Region is One of the Equal Part.
17/15 as a mixed number is 1 2/15. 2 31/18 as a mixed number is 54 13/18.
By conservation of momentum,
(110.0 kg) (1.5 ms⁻¹) + (170.0 kg) (-2.0 ms⁻¹) = (110.0 kg) (-2.75 ms⁻¹) + (170.0 kg) v
where v is the final velocity of the second car.
Solve for v :
-175 kg•ms⁻¹ = -302.5 kg•ms⁻¹ + (170.0 kg) v
127.5 kg•ms⁻¹ = (170.0 kg) v
v = (127.5 kg•ms⁻¹) / (170.0 kg) = 0.75 ms⁻¹
