The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
You multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 3x^2y
You could four times because there are four letters in the word cube, so there are only four possible ways you could spell it.
Hope this helps:)
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Answer:
Step-by-step explanation:
<h2>4/x=2/10</h2>
cross multiplication:
4*10=2*x
40=2x
x=40/2=20
<h2>w/2 = 4.5/6.8</h2>
6.8w=2(4.5)
6.8w=9
w=9/6.8=1.32352941