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IrinaK [193]
3 years ago
11

Plzzz!!!!!!!! Help me !!!!!!!!!

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

The answer after division is: 2\frac{2}{5}

Step-by-step explanation:

The given question involves two mixed fractions that are being divided.

7\frac{1}{2}\div 3\frac{1}{8}

First of all, we will convert the fractions into proper fractions

\frac{15}{2}\div \frac{25}{8}

When the division is performed, the second fraction is reversed

So dividing gives us:

\frac{15}{2} * \frac{8}{25}\\= \frac{3*4}{5}\\=\frac{12}{5} = 2\frac{2}{5}

Hence,

The answer after division is: 2\frac{2}{5}

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dem82 [27]

Answer:

firstly covert it like 7   1/4

= 4x7+1 = 29 so 29/4

Step-by-step explanation:

and then find difference by making denominators same

7 0
4 years ago
Help plz anything works
Drupady [299]

5 weeks -> $20

Divide 5:

1 week -> $4

Replace week with "w" and $ with "s"

w=4s

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3 years ago
Which inequality represents all possible solution of -6n< -12
sashaice [31]

Answer:

less than

Step-by-step explanation:

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NEED HELP!!!!!<br> .................................
konstantin123 [22]

Answer:

X= 5

Step-by-step explanation:

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Help please somebody ASAP
Firlakuza [10]

Answer:

\frac{-2x+11}{(x-4)(x+1)}

Step-by-step explanation:

I don't think we can factor this so we'll have to multiply to make the denominators the same

\frac{3(x+1)}{(x^2-3x-4)(x+1)}-\frac{2(x^2-3x-4)}{(x+1)(x^2-3x-4)}\\\\\frac{3x+3-(2x^2-6x-8)}{(x^2-3x-4)(x+1)}=\frac{-2x^2+9x+11}{(x^2-3x-4)(x+1)}\\-2x^2+9x+11=(x+1)(-2x+11)\\\\x^2-3x-4=(x+1)(x-4)\\\frac{(x+1)(-2x+11)}{(x+1)(x-4)(x+1)}=\frac{-2x+11}{(x-4)(x+1)}

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