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cricket20 [7]
3 years ago
10

Last year the 7th grade class had 350 students. This year the number decreased 36%. How many students are in this year's 7th gra

de class?
Mathematics
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

224

Step-by-step explanation:

350-36%=224. easy as that.

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Rina8888 [55]
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For the past ten years, Michelle has been tracking the average annual rainfall in Boynton Beach, Florida by recording her data i
Sedbober [7]

Answer:

See explanation

Step-by-step explanation:

The average rainfall when you add all 10 years of rainfall up and divide by 10 is an average of 59.946 inches of rain each year. The equation for the data is y = -0.53x + 64.45, this means that the rainfall is getting less each year at a -0.53 inches of rain each year.

x = year (2004 would be 4, etc)

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3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
3 years ago
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julsineya [31]

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First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:

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8 0
4 years ago
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frez [133]

Answer:

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