If you would like to find the discriminant of the quadratic equation 0 = 2x^2 + 3x - 5, you can do this using the following steps:
<span>0 = 2x^2 + 3x - 5
0 = ax^2 + bx + c
a = 2, b = 3, c = - 5
</span>D = b^2 - 4 * a * c = 3^2 - 4 * 2 * (-5) = 9 + 40 = 49
The correct result would be 49.
Well, you can do that by many ways like:
If you have value of B & P or B & H, you can find the other one by the formula,
H² = P²+B²
Then, you can easily calculate the value of sine by putting P/H
Hope this helps!
Answer:
n = π/6, π/4, 3π/4, 5π/6
Step-by-step explanation:
sin(3n) − sin n = cos(2n)
Use double and triple angle formulas:
(3 sin n − 4 sin³ n) − sin n = 1 − 2 sin² n
2 sin n − 4 sin³ n = 1 − 2 sin² n
4 sin³ n − 2 sin² n − 2 sin n + 1 = 0
Factor by grouping:
2 sin² n (2 sin n − 1) − (2 sin n − 1) = 0
(2 sin² n − 1) (2 sin n − 1) = 0
Solve:
2 sin² n − 1 = 0
2 sin² n = 1
sin² n = 1/2
sin n = √2/2
n = π/4, 3π/4
2 sin n − 1 = 0
2 sin n = 1
sin n = 1/2
n = π/6, 5π/6