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Sonbull [250]
3 years ago
15

The base of a triangular prism is a right triangle whose legs are 9 cm and 12 cm. The height of the prism is 33 cm. What is the

lateral area of the prism? Complete the explanation on how you can find the answer.
You can use the _____
to find the hypotenuse of the base, _____
cm. Then, multiply the perimeter of the base, ______
cm, by the height, _____
cm. The lateral area of the prism is _____
square centimeters.
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0

please mark as brainliest

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Solve for T. B=RT-4/6​
lions [1.4K]
I’m not sure which of these you meant to type so I answered both ways
B=(RT-4)/6 multiply by 6
6B= RT-4. Add 4
6B+4= RT. Divide by R
(6B+4)/R = T


Or B=RT -4/6. Multiply by 6
6B=6RT -4. Add 4
6B+4= 6RT. Divide by 6R
(6B-4)/6R = T. Reduce
(3B-2)/3R = T
8 0
3 years ago
The volume of a cube is 512 cm3 . What is the area, in square centimetres, of each side of the cube?
lesantik [10]

Answer:

Step-by-step explanation:

V of a cube is s^3

V = 512

s = cube root of (V)

s = cube root of 512 cm^3

s = 8

The area of one face of the cube is s^2

s = 8

Area 1 face = 8^2

Area of 1 face = 64 cm^2

4 0
1 year ago
Someone please help me
Free_Kalibri [48]
D. y = 3x + 2

Check (-4, -10)
-10 = 3(-4) + 2
-10 = -12 + 2
-10 = -10 :)

Check (-3, -7)
-7 = 3(-3) + 2
-7 = -9 + 2
-7 = -7 :)

Check (-2, -4)
-4 = 3(-2) + 2
-4 = -6 + 2
-4 = -4 :)

Check (-1, -1)
-1 = 3(-1) + 2
-1 = -3 + 2
-1 = -1 :)

Check (0, 2)
2 = 3(0) + 2
2 = 0 + 2
2 = 2 :)
4 0
2 years ago
18 POINTS WILL GIVE BRAINLIEST !!
lys-0071 [83]

Answer:

28

Step-by-step explanation:

The interior triangle has a right angle, and one of its corners is 62, so the other angle, which is vertical to x, is 180-(90+62)=28, so x=28.

8 0
3 years ago
Read 2 more answers
My other equation for a dfferent problem is 1+y=-4/5x-2 ​
slava [35]

Answer:

y-intecept= positive 6

slope is 3/8

Step-by-step explanation:

y−6= 3/8x This is standard form

change to slope-intercept form

y=mx+b

m=slope

b=y-intercept

y= 3 /8 x+6

5 0
2 years ago
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