All categories

4 years ago

Select the function that represents the simple interest formula.

Mathematics

2 answers:

Anit [1.1K]4 years ago

8 0

Answer:

D. A(n) = P + (n-1)i*P

Step-by-step explanation:

The formula to calculate the simple interest is:

$SI = \frac{Pnr}{100}$

Replace i by $\frac{r}{100}$ , then

SI = Pni

where n is the number of years.

So, for n-1 years, the simple interest is:

SI = P(n-1)*i

The Total amount is:

A(n) = P + (n-1)i*P

stiv31 [10]4 years ago

4 0

Answer:

The answer is D on apex. I just took the test, hope I could help :)

Step-by-step explanation:

You might be interested in

Write a word problem in which you multiply two decimals the product should be between 0 and 1

Lena [83]

Potatoes cost $1.20 / kg. If you buy 0.8 kg, how much are the potatoes? (Answer $0.96)

8 0

4 years ago

How are conditional probability and independent events related?

artcher [175]

Answer:

1. P(A|B) - option 2

2. does not affect - option 2

3. P(A) - option 1

Step-by-step explanation:

By the definition, the notation P(A|B) reads the probability of event A given that event B has occured. So, for the first gap correct choice is 2 - P(A|B).

If events A and B are independent, then the probability of event B occuring does not affect the probability of event A occuring. So, for the second gap correct choice is 2 - does not affect.

Events A and B are independent, then

$P(A\cap B)=P(A)\cdot P(B)$

Use formula for the conditional probability:

$P(A|B)=\dfrac{P(A\cap B)}{P(B)}$

Since events A and B are independent, we get

$P(A|B)=\dfrac{P(A)\cdot P(B)}{P(B)}=P(A)$

So, for the third gap correct answer is 1 - P(A)

8 0

4 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$