1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
The first one seems more reasonable
Answer: each girl received 30 stickers.
Step-by-step explanation:
Let x represent the number of stickers that the boys received.
Let y represent the number of stickers that the girls received.
The total number of children was 42. 2/3 of the children were boys. It means that the number of boys were
2/3 × 42 = 28
The number if girls would be
42 - 28 = 14
The total number of stickers that the school principal shared was 840. It means that
28x + 14y = 840- - - - - - - - -1
Each of the boys received the same number of stickers while each girl received twice as many as each boy. It means that
y = 2x
Substituting y = 2x into equation 1, it becomes
28x + 14 × 2x = 840
28x + 28x = 840
56x = 840
x = 840/56
x = 15
y = 2x = 15 × 2
y = 30
Answer:
26.9
Step-by-step explanation:
Right now we have '8' in the tenths place. That '6' following the '8' requires us to round up. Thus, 26.86 to the nearest tenth is 26.9.
Answer:
Step-by-step explanation:
10x + 12y is the correct answer
