3 years ago

Electromagnetic radiation is used primarily for what?

Physics

2 answers:

valina [46]3 years ago

7 0

Answer:

A is correct I took the test

Explanation:

jek_recluse [69]3 years ago

3 0

C - to carry wavelength

You might be interested in

If a spring requires 20 Newtons to be compressed a distance of 10 centimeters, what is the spring constant in N/m (newton meters

Lady bird [3.3K]

Answer:

20 N / 0.1 meters

Explanation:

10 centimetres is equal to 1 tenth of a meter or 0.1 meters.

6 0

3 years ago

The momentum of a car 54,400 kg * m/s. If the car weighs 16,680N what is the velocity of the car

wariber [46]

G=mg=>m=G/g=16680/9.8=1702 kg

p=mv=>v=p/m=54400/1702=32 m/s

6 0

3 years ago

Read 2 more answers

PLS HELP

Kazeer [188]

The answer would be letter choice B

7 0

3 years ago

Objects with masses of 135 kg and a 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects o

IrinaVladis [17]

Answer:

The net gravitational force on the mass is $1.27\times 10^{-5}$

Explanation:

We have by Newton's law of gravity the force of attraction between masses $m_{1},m_{2}$

$F_{att}=G\frac{m_{1}m_{2}}{r^{2}}$

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

$F_{1}=6.67\times 10^{-11}\frac{135\times 38}{(0.25)^{2}}\\\\F_{1}=5.47\times 10^{-6}N$

Force of attraction between 435 kg mass and 38 kg mass is

$F_{2}=6.67\times 10^{-11}\frac{435\times 38}{(0.25)^{2}}\\\\F_{2}=1.76\times 10^{-5}N$

Thus the net force on mass 38.0 kg is $F_{2}-F_{1}=1.76\times 10^{-5}-5.47\times 10^{-6}\\\\F_{2}-F_{1}=1.27\times 10^{-5}$

8 0

4 years ago

What is a watt equivalent to in terms of kilograms, meters and seco

Ierofanga [76]

1 watt = 1 joule per second

1 joule = 1 newton-meter

1 newton = 1 kg-meter per second²

Put it all together and you have . . .

1 watt = 1 <em>kg-meter² / second³

</em>

5 0

3 years ago