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mixer [17]
3 years ago
9

Youare on a train travelling northat 80.0m/s relative to the ground. The air is still relativetothegroundwhen you hear the whist

le of atraintravellingsouth. You know that train whistles are emitted with a frequency of 262Hz, but the whistle appears to have a frequency of 350Hz. What is the speed of the other train?
Physics
1 answer:
AURORKA [14]3 years ago
3 0

To solve this problem we will apply the concepts related to the Doppler effect. This is understood as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically this is given as,

f = \frac{v \pm v_r}{v \pm v_s}(f_0)

Here,

v = Speed of the waves in the middle

v_r = Speed of the receiver in relation to the medium (Positive if the receiver is moving towards the transmitter or vice versa)

v_s = Speed of the source with respect to the medium (Positive if the source moves away from the receiver or vice versa)

Our values are given as,

v = 342m/s

f_0 = 262Hz

v_r = 80m/s

f = 350Hz

Replacing,

350 = \frac{342+80}{342-v} (262)

Solving for the velocity of the source,

v = 26.1m/s

Therefore the speed of the other train is 26.1m/s

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True, they had a hole in their hip socket that allowed them to run faster than other reptiles of their size at the time. As well as most reptiles besides reptiles had legs to the side, rather than under them like dinosaurs did.

Hope this helps!
5 0
4 years ago
The average rate of disappearance of ozone in the reaction is
olasank [31]

Answer:

1.3 x 10^(-2) atm/s

Explanation:

It follows the stoichiometry. For every mole of O3 that disappears, 1.5 moles (that is, 3/2) of O2 appears:

1.5 * 0.009 atm/s = 0.0135 atm/sec; the answer is 1.3 x 10^(-2) atm/s

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3 years ago
What is relation of acceleration of a body to its mass and applied force​
irinina [24]
The law states that external forces cause objects to accelerate, and the amount of acceleration is directly proportional to the net force and inversely proportional to the mass of the object.


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3 0
4 years ago
Which of the following planets were the ancient Greeks able to see and make careful observations of?
zepelin [54]

Answer:

Neptune and Uranus

Explanation:

Did a quiz on this not to long ago

5 0
3 years ago
As mentioned in the text, the tangent line to a smooth curve r(t) = ƒ(t)i + g(t)j + h(t)k at t = t0 is the line that passes thro
LiRa [457]

Answer:

x = t

y = \frac{1}{3}t

z =t

Explanation:

Given

r(t) = f(t)i + g(t)j + h(t)k at t = 0

Point: (f(t0), g(t0), h(t0))

r(t) = ln\ t_i + \frac{t-1}{t+2}j + t\ ln\ tk, t0 = 1 -- Missing Information

Required

Determine the parametric equations

r(t) = ln\ ti + \frac{t-1}{t+2}j + t\ ln\ tk

Differentiate with respect to t

r'(t) = \frac{1}{t}i +\frac{3}{(t+2)^2}j + (ln\ t + 1)k

Let t = 1 (i.e t0 = 1)

r'(1) = \frac{1}{1}i +\frac{3}{(1+2)^2}j + (ln\ 1 + 1)k

r'(1) = i +\frac{3}{3^2}j + (0 + 1)k

r'(1) = i +\frac{3}{9}j + (1)k

r'(1) = i +\frac{1}{3}j + (1)k

r'(1) = i +\frac{1}{3}j + k

To solve for x, y and z, we make use of:

r(t) = f(t)i + g(t)j + h(t)k

This implies that:

r'(1)t = xi + yj + zk

So, we have:

xi + yj + zk  = (i +\frac{1}{3}j + k)t

xi + yj + zk  = it +\frac{1}{3}jt + kt

By comparison:

xi = it

Divide by i

x = t

yj = \frac{1}{3}jt

Divide by j

y = \frac{1}{3}t

zk = kt

Divide by k

z = t

Hence, the parametric equations are:

x = t

y = \frac{1}{3}t

z =t

3 0
3 years ago
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