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Ipatiy [6.2K]
2 years ago
15

How do I solve for y in the equation 2(3/4)+y=4?

Mathematics
2 answers:
yuradex [85]2 years ago
5 0
2* .75 + y = 4
1.5 + y = 4
Subtract 1.5 From Each Side
Y = 2.5 Or 2 1/2
beks73 [17]2 years ago
3 0
Yea the other person is right.. the answer is Y= 2.5 or 5/2 or 2 1/2
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Which equation represents a quadratic function?<br> y = x2<br> y = 2x<br><br> y =1/x^2
ehidna [41]

Answer:

  y = x²

Step-by-step explanation:

A quadratic function is a polynomial function that has a variable to the power of 2 as the highest degree term. y = 1/x^2 is not a polynomial. y=2x is a linear function.

  y = x^2 is a quadratic function

3 0
3 years ago
How many even numbers less than 1000 can be formed from the given
Vinil7 [7]

Answer:

non of them it should be 32 iʻm pretty sure

Step-by-step explanation:

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3 years ago
Adrian purchases 6 tubes of paint and 3 paintbrushes at a craft store. Each tube of paint costs $2.50 and each paintbrush costs
Airida [17]

Answer:

$14.50

Step-by-step explanation:

6 x $2.50 = $15.00

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$15.00 + $1.50 = $16.50

$16.50 - $2.00 = $14.50

8 0
3 years ago
Read 2 more answers
Find the volume of a cube with a side length of 4r3s2.
andrey2020 [161]

Answer:

V = 64 r^(9) * s^(6)

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = (  4r^3s^2) ^3

We know that ( ab) ^c = a^c * b^c

V = 4^3 * r^3^3  * s^2^3

V = 64 * r^3^3  * s^2^3

   We know that a^b^c = a^(b*c)

V = 64 r^(3*3) * s^(2*3)

V = 64 r^(9) * s^(6)

8 0
3 years ago
Find the distance between the two numbers on a number line. Write your answer as a fraction in simplest form. - 7/9, - 2/9 The d
Nesterboy [21]

The distance between the two points on the number line is of \mathbf{\frac{5}{9}} units.

-------------------------------------------

  • The distance between two numbers on the number line is given by the <u>subtraction of the greater by the smaller number.</u>
  • The greater number is -\frac{2}{9}
  • The smaller is -\frac{7}{9}.
  • The distance is:

-\frac{2}{9} - (-\frac{7}{9}) = -\frac{2}{9} + \frac{7}{9} = \frac{-2 + 7}{9} = \frac{5}{9}

Thus, distance of \mathbf{\frac{5}{9}} units.

A similar problem is given at brainly.com/question/10795861

8 0
2 years ago
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