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Aloiza [94]
3 years ago
9

Someone pls help me I'm stuck on this question!!!!????

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
The answer is $414.00
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This is a quiz on special right triangles. please help me i cannot fail this. i will mark brainliest
kobusy [5.1K]

Answer:

x=4

Step-by-step explanation:

Consider ΔKLJ:

sinθ=opposite/hypotenuse

sin30=LJ/8√2

LJ=0.5*8√2=4√2

Consider ΔMLJ:

sinθ=opp/hyp

sin45=x/4√2

1/√2=x/4√2

4√2/√2=x

x=4

4 0
3 years ago
PLEASE help with these questions??<br> there are 7 of them!<br> Thank you!!
svetlana [45]
We know in these kind of triangles that have a 90 degrees angle, we can do:

{a}^{2} + {b}^{2} = {c}^{2}

so the first question:

\sqrt{ {99}^{2} + {20}^{2} } = 101

and then:

b = \sqrt{ {17}^{2} - {15}^{2} } = 8

so , when you want to rationalize , usually you must multiply the irrational factor as 1:

\frac{ \sqrt{15} }{ \sqrt{15} } = 1

so , now multiply:

\frac{3}{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{3 \sqrt{15} }{15} = \frac{ \sqrt{15} }{5}

in the next question,we know negative numbers in radical don't have any solution so 2 is correct,

4 0
3 years ago
Please helllp!!! will give 50 points!!!!​
Anon25 [30]
Angle 8,2 that’s the answer
3 0
3 years ago
Read 2 more answers
A gear with a diameter of 12.0 inches makes 35 revolutions every three minutes. Find the linear and angular velocities of a poin
alina1380 [7]

Answer:

Angular velocity: \omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

Linear velocity: v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

Step-by-step explanation:

The gear experiments a pure rotation with axis passing through its center, the angular (\omega), in radians per second, and linear velocities (v), in inches per second, of a point on the outer edge of the element are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n (1)

v = R\cdot \omega (2)

Where:

\dot n - Rotation rate, in revolutions per minute.

R - Radius of the gear, in inches.

If we know that \dot n = \frac{35}{3}\,\frac{rev}{min} and R = 12\,in, then the linear and angular velocities of the gear are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n

\omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

v = R\cdot \omega

v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

7 0
3 years ago
Freeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Allisa [31]

Answer:

Woooooow

Good

Eeeeeeeeeeeeeeer

5 0
3 years ago
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