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Anton [14]
3 years ago
8

Which method is not used to find the solution of a system of linear equations. guess and checkA. graphingB. substitutionC. matri

ces
Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

guess and check

Step-by-step explanation:

Linear equation systems usually have two or more variables to find.

The values for these variables can be found by different methods, some of them are indeed graphing, substitution and with matrices.

So these are correct options that are used to solve linear systems of equations.

On the other hand, the guess and check method is not used to find the solution of these systems, since the more variables the system has the more difficult it is to guess the answer,<u> the graphic and mathematical methods are more effective and reliable.</u>

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Which equation represents a line parallel to the line shown on the graph?
Mama L [17]

Answer:

-3x+3

Step-by-step explanation:

The equation to the line shown is formed as follows.

It passes through the points (-6,0) and (-8,6)

The gradient of the line=Δy/Δx

=(y₂-y₁)/(x₂-x₁)

=(6-0)/(-8--6)

=6/-2

=-3

The line parallel to the line shown has the same gradient i.e -3

Therefore the line in question is

-3x+3.

7 0
3 years ago
How do I work this out?
Crank

Answer:

$503.90

Step-by-step explanation:

6500 X .93= 6045

6045/12=503.90

8 0
3 years ago
Read 2 more answers
Help me with this question i tried multiple time to solution it always wrong
maw [93]
7/9-1/3 or 7/9-3/9= 4/9 is the answer
4 0
2 years ago
Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop
Archy [21]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}

4 0
1 year ago
Please help me get the right answer?!
Aleksandr-060686 [28]
The answer is A, \frac{1}{81}. This is because when plugging in -2 for x, the expression will look like this: 9^{-2}. To make the exponent positive, you have to flip it into a fraction. Then it will be \frac{1}{9^2}. Lastly, you simplify the denominator into 81.
4 0
3 years ago
Read 2 more answers
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