PLEASE HELP ME I WILL GIVE U BRAINLEAST!!!!!

Connor has a collection of dimes and quarters with a total value of $6.30. The number of dimes is 14 more than the number of qua

Anarel [89]

Connor has 14 quarters and 28 dimes.

Step-by-step explanation:

Given,

Worth of coins = $6.30 = 6.30*100 = 630 cents

We know that,

1 quarter = 25 cents

1 dime = 10 cents

Let,

Quarter = x

Dime = y

According to given statement;

25x+10y=630 Eqn 1

The number of dimes is 14 more than the number of quarters

y = x+14 Eqn 2

Putting value of y from Eqn 2 in Eqn 1

$25x+10(x+14)=630\\25x+10x+140=630\\35x=630-140\\35x=490$

Dividing both sides by 35

$\frac{35x}{35}=\frac{490}{35}\\x=14$

Putting x=14 in Eqn 2

$y=14+14\\y=28$

Connor has 14 quarters and 28 dimes.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

4 0

3 years ago

The sanctuary currently has 125 exotic fish. The average amount of the tank allotted for each fish is represented by the binomia

sveta [45]

Does anyone wanna help me with something ill give u bloxburg (from ro _blox) money if u know how to do it!And yes it’s math Oudh

6 0

2 years ago

The length of a rectangle is twice its width the perimiter is 60 ft find its area

Masja [62]

Hello,

let's assume a=the length and b the width.

$\left\{\begin{array}{ccc}a&=&2*b\\2(a+b)&=&60\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\a+b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\3b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b&=&10\\a&=&20\\\end{array}\right.\\\\\\Area=10*20=200\ (ft^2)\\$

4 0

3 years ago

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out o

Nuetrik [128]

We have the function

$p(t)=550(1-e^{-0.039t})$

Therefore we want to determine when we have

$p(t_0)=550$

It means that the term

$e^{-0.039t}$

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

$e^{-0.039t}\rightarrow0$

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

$\alpha=\frac{1}{0.039}$

The inverse of the number, but why do that? look what happens when we do t = α

$e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}$

And when t = 2α

$e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}$

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

$e^{-0.039t}\approx0$

Only using powers of e

Let's write some inverse powers of e:

$\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}$

See that at t = 5α we have a small value already, then if we input p(5α) we can get

$\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}$

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

$\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}$

7 0

1 year ago

Situation:

zloy xaker [14]

Answer:

mass at tika is the answer of that question answer

7 0

3 years ago