PLEASE HELP ME I WILL GIVE U BRAINLEAST!!!!!

Find the slope of the graph of the equation

sammy [17]

Answer:

y=-1/2x+2

Step-by-step explanation:

slope is -1/2 beware this is a negitive slope so it goes down like this \

go one up and go to the left 2 times and connect the dots

6 0

2 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

What is the difference between-4 and 6 1. -10 2. -2 3. 2 4. 10

earnstyle [38]

Answer:

It is 1, 2, 3, or 4

Step-by-step explanation:

8 0

2 years ago

From 4a + 7b - 12c subtract 8a - 9b + 12d.

ollegr [7]

Answer:

-4a + 16b -12c -12d

Step-by-step explanation:

Given: From 4a + 7b - 12c subtract 8a - 9b + 12d.

We are given two algebraic expression. We can add/subtract only the like terms.

(4a + 7b -12c) - (8a -9b +12d)

Now we have distribute the negative sign inside the second expression (8a -9b +12b). If we do, the sign changes.

4a + 7b -12c -8a + 9b -12d [Sign rule: -(-) = +; -(+) = -]

Now we can combine the like terms

= (4a - 8a) +(7b + 9b) -12c -12d

= -4a + 16b -12c -12d

8 0

2 years ago

Which of the following would be an example of a service?

RoseWind [281]

Answer:

A, a waiter serving food

Step-by-step explanation:

a waiter is being of service by taking your order so it can be prepared

7 0

3 years ago