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VMariaS [17]
3 years ago
13

DRAW TWO LINES THAT BOTH REPRESENT PROPONTINAL RELATIONSHIPS BUT HAVE DIFFRENT SLOPES LABEL ONE LINE A AND OTHER B

Mathematics
2 answers:
Sophie [7]3 years ago
4 0

Answer:

may i see the question

Olin [163]3 years ago
3 0

Answer:

gjtudt57uydt57uy

Step-by-step explanation:

yhrsy4ry64eyhdrt

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what's the probability and the deck of cards have 52 cards what's the probability of picking a black card
olga nikolaevna [1]
There is a 26 percent chance of picking one since there are only 2 colors black and red
4 0
4 years ago
Read 2 more answers
Assuming that workers' salaries in your company are uniformly distributed between $15,000 and $40,000 per year, find the probabi
lord [1]

Answer:

The  probability is  P(\$20,000 <  X < \$35,000) =  0.6

Step-by-step explanation:

From the question we are told that

     Workers' salaries in your company are uniformly distributed between $15,000 and $40,000 per year

  Generally the probability that a randomly chosen worker earns an annual salary between $20,000 and $35,000 is mathematically represented as

        P(\$20,000 <  X  \$35,000) =  \frac{ 35000 -  20000}{ 40000 - 150000}

  => P(\$20,000 <  X < \$35,000) =  0.6

     

3 0
4 years ago
in a parade, each tricycle and bicycle have one rider.There are 64 wheels and 28 riders.How many tricycles are there? can you sh
Ann [662]

Answer:

8 tricycles

Step-by-step explanation:

Make a system of equations

Let t represent tricycles, and b represent bicycles

We know that tricycles have 3 wheels, bicycles have 2, and there are a total of 64 wheels

We also know each has one rider, and there are a total of 28 riders

3t+2b=64

t+b=28

Subtract t from both sides in the second equation. This will allow us to use substitution

b= -t+28

Substitute -t+28 in for b in the first equation

3t+2b=64

3t+2(-t+28)=64

Distribute the 2

3t + 2*-t+ 2* 28 =64

3t-2t+56=64

Combine like terms

t+56=64

Subtract 56 from both sides

t=8

There were 8 tricycles

4 0
3 years ago
Read 2 more answers
As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos
hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

Number of bulbs are tested = 3.

Please note, when order it not important, we apply combination.

Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

^nCr = \frac{n!}{(n-r)!r!} read as r out of n.

Plugging n=100 and r=3 in above formula, we get

^100C3 = \frac{100!}{(100-3)!3!}

Expanding 100! upto 97!, we get

=\frac{100\times 99\times 98\times 97!}{97!3!}

Crossing out common 97! from top and bottom, we get

=\frac{100\times 99\times 98}{3!}

Expanding 3!, we get

=\frac{100\times 99\times 98}{3\times 2\times 1}

= 100 × 33  × 49

= 161700 ways.

<h3>Therefore,  by 161700 ways this test batch can be chosen.</h3>
3 0
4 years ago
PLS HELP GIVING BRAINLIEST DUE SOON!!!
UkoKoshka [18]

Answer:

102 and 102

72 and 72

142 and 142

Step-by-step explanation:

5 0
3 years ago
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