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1 year ago

Could someone help me please?

Mathematics

1 answer:

AlekseyPX1 year ago

3 0

Pretty sure the one of the left is higher than the one on the right

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What is the value of f(−1) when f(x) = 2x + 2 f(−1)=

Elza [17]

F(-1)=2*(-1)+2
f(-1)=2-2
f(-1)=0

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2 years ago

A, B and C form the vertices of a triangle. BC = 6.9cm and ∠ CBA = 137°. Given that the area of the triangle is 12.6cm^2, calcul

Anon25 [30]

Answer:

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Step-by-step explanation:

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2 years ago

1. P(x)=x^2+2 2. P(x)= 2x +10

ruslelena [56]

Answer:

see explanation

Step-by-step explanation:

Since p(x) = x² + 2 , if x ≤ 4

For x = 4 then this is included in the inequality x ≤ 4

whereas x > 4 does not include x = 4 but values greater than 4

Thus to evaluate x = 4 use p(x) = x² + 2

4 0

2 years ago

If the angle of a sector measures 60°, what fraction of the circle is the sector?

maks197457 [2]

The angle of the sector is also equal to the arc measure of the circle. This is because a sector is made up of two radii of a circle.

A circle is 360 degrees.

60 / 360 = 1/6

The sector is 1/6 of the circle.

Hope this helps!! :)

6 0

2 years ago

Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

Altitude is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

$f=\frac{10^{2}-5^{2}}{10}$

f = 7.5

The length of $\overline{AC}$ is

$\overline{AC}=f+5$

$\overline{AC}=7.5+5$

$\overline{AC}=12.5$

The length of the hypotenuse of triangle ABC is 12.5 units.

5 0

2 years ago

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