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2 years ago

Could someone help me please?

Mathematics

1 answer:

AlekseyPX2 years ago

3 0

Pretty sure the one of the left is higher than the one on the right

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I need help with this please

Ksenya-84 [330]

I’m not sure bc i did this years ago but u might want to go to ur teacher for some help

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3 years ago

Evaluate the algebraic expression 5 + 9(x-8)2 for x = 9.<br> When x = 9,5+9(x-8)2 =

Lena [83]

23. 5+9((9)-8)2, 5+9(1)2, 5+18=23

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2 years ago

one each day dariene write in her personal diary and records whether the sun isshining or not when she looked back tough her dia

Svetradugi [14.3K]

Im guessing ten or some sort of factor of ten

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3 years ago

Read 2 more answers

What are the values of x and y in the equation

vaieri [72.5K]

Answer:

The correct choice is D

Step-by-step explanation:

Value of X=20 and then to know the value of y we need to add

52+52= 104

360-104= 256

256÷2= 128

Y=128

5 0

2 years ago

List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct

zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$

Where:

$\bar x$ = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

$\bar x$ = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

$C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }$

$\sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{0.872}}$

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0

3 years ago