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3 years ago

Sam picked 48 oranges in 5 minutes. How many oranges could she pick in 2 minutes?

Mathematics

1 answer:

STatiana [176]3 years ago

6 0

Step-by-step explanation:

48 oranges in 5 minutes means she picked 48 oranges in 300 seconds.

Divide 48 by 300 to get what she would pick in one second.

This equals 0.16

Multiply 0.16 by 120 seconds [how many seconds are in two minutes].

This equals 19.2 oranges in two minutes. As she cannot pick 0.2 of an orange, she could pick 19.

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The volume of a rectangular prism is found using the formula V = l · w · h, where l is the length, w is the width, and h is the

Anastaziya [24]

There are additional details to the problem that you have left out. I have found them in other resources. The tray has to be 3 centimeters high and the length is five centimeters longer than its width. The volume of the tray is 252 cubic centimeters.

With these given, we can find the equation with the width alone as the variable:

$V=lwh$
$252=(x+5)(x)(3)$
$84= x^{2} +5x$

To know if it's possible for the width to be 7.5 centimeters, we just plug this as the value of x and see if it satisfies the equation:

$84= (7.5)^{2} +5(7.5)$
$84= (7.5)^{2} +5(7.5)$
$84=93.75$

As we can see, the equation was not satisfied therefore it is NOT possible for the width to be 7.5 centimeters.

8 0

3 years ago

How can you find f(2) if f(x)=−3x2−7?

Mnenie [13.5K]

Step-by-step explanation:

F(2)=3(2)²-7

................

7 0

3 years ago

sum of all positive integers that are both less than 100 and each number has exactly 5 positive integral facctors

kati45 [8]

Answer:

144

Step-by-step explanation:

1×2×3×4×x=48x<100

x<100/48

or x<25/12

but x is an integer

so x=1,2

48×1=48

48×2=96

reqd. sum=48+96=144

7 0

4 years ago

The diagonals of a rhombus are 14 and 48cm. Find the length of a side of the rhombus.

FromTheMoon [43]

Step-by-step explanation:

Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.

Since, diagonals of a rhombus are perpendicular bisector.

$\because \: OA = \frac{1}{2} \times AC \\ \\ \therefore \: OA = \frac{1}{2} \times 14 \\ \\ \huge \red{ \boxed{\therefore \: OA = 7 \: cm}} \\ \\ \because \: OB = \frac{1}{2} \times BD \\ \\ \therefore \: OB = \frac{1}{2} \times 48 \\ \\ \huge \red{ \boxed{\therefore \: OB = 24 \: cm}} \\ \\ In \: \triangle OAB, \: \: \angle AOB=90° \\ \therefore \: by \: Pythagoras \: Theorem \\ AB= \sqrt{OA^2 +OB^2 } \\ = \sqrt{7^2 +24^2 } \\ = \sqrt{49+576 } \\ = \sqrt{625 } \\ \huge \orange{ \boxed{\ \therefore \:AB= 25 \: cm.}}$

Hence, length of a side (or all) is 25 cm.

3 0

4 years ago

13/20 as a percent and 7/25 as a percent to no need to show work just need the straight up percent

Ivahew [28]

13/20 = 65%
7/25 = 28%

4 0

3 years ago