Answer:
..........
Step-by-step explanation:
..........
The slope of the line of best fit to the raw-score scatter plot is 0.98
- The equation is y = 0.98x - 3.74
- The value of y given that x = 12 is 8.02
<h3>How to determine the slope of the line?</h3>
From the question, we have the following parameters that can be used in our computation:
- Standard deviations of X, Sx = 1.88
- Standard deviations of Y, Sy =2.45
- Correlation coefficient, r between X and Y = 0.75
The slope (b) of the line is calculated as
b = r * Sy/Sx
Substitute the known values in the above equation, so, we have the following representation
b = 0.75 * 2.45/1.88
Evaluate
b = 0.98
<h3>The equation of the line of best fit</h3>
A linear equation is represented as
y = bx + c
Where
Slope = b
y-intercept = c
In (a), we have
b = 0.98
So, we have
y = 0.98x + c
Recall that the point (13, 9) is on the line of best fit.
So, we have
9 = 0.98 * 13 + c
This gives
9 = 12.74 + c
Evaluate
c = -3.74
So, we have
y = 0.98x - 3.74
<h3>The value of y from x</h3>
Here, we have
x = 12
So, we have
y = 0.98 x 12 - 3.74
Evaluate
y = 8.02
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Answer:A. y ≥ 2
Step-by-step explanation:
First the line is solid, a complete line not dotted so the inequality sign to use is : ≥ or ≤
The points have their y-coordinate vale as 2, (−5, 2) and (3, 2), this means the line crosses the y-axis at y=2 but because the shaded part is above this line, then the correct inequality will be :
y ≥ 2
Answer:
132cm^2
Step-by-step explanation:
first break the shape up into component shapes. the shape is made of two rectangles and two triangles. the area for a rectangle is A=BH where b is base and h is height. the area of a right triangle is BH/2 where b is the base and h is the height. you are given the base and height of the top rectangle 4x7. To find the area of the triangles and the second rectangle you have to do some algebra. the total base length is 19cm and the top rectangle has a length of 7cm so 19-7 leaves you with 12cm to spare and there is two symmetric triangles on each side so 12/2 is 6. now we know all the measurements and can solve.