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inysia [295]
3 years ago
13

Multiply. 4x2 (2x3 + x2 - 3) A. 8x6 + 4x4 + 12x2 B. 8x6 + 4x - 12x2 C. 8x5 + 4x4 - 12x2 D. 8x5 + 4x4 + 12x2​

Mathematics
1 answer:
love history [14]3 years ago
7 0

Answer:

\boxed{  \bold{\sf{ { \boxed{ \sf{8 {x}^{5}  + 4 {x}^{4}  - 12 {x}^{2} }}}}}}

Option C is the correct option.

Step-by-step explanation:

\sf{4 {x}^{2} (2 {x}^{3}  +  {x}^{2}  - 3})

Distribute 4x through the parentheses.

\dashrightarrow{ \sf{4 {x}^{2}   \times \: 2 {x}^{3}  + 4 {x}^{2}   \times  {x}^{2}    - 4 {x}^{2}   \times 3}}

\dashrightarrow{ \sf{8 {x}^{5}  + 4 {x}^{4}  - 12 {x}^{2} }}

Hope I helped!

Best regards! :D

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I don't think that there is two same results. sorry I couldn't help

Step-by-step explanation:

for I the answer should be 10 if you replaced each x by 2. f(2) = 3(2) + 4

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A proportional relationship is a relationship which crosses through the origin (0,0) and which has a proportional constant. We can determine this either by finding (0,0) where x=0 and y=0 in the table or by dividing y/x. None of the tables contain (0,0) so we will divide y by x. We are looking for a table which when each y is divided by its x we have the same constant appearing.

<u>Table A</u>

\frac{12}{3} \neq \frac{15}{6} \neq \frac{18}{8} \neq \frac{20}{10}

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<u>Table B</u>

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<u>Table D</u>

\frac{7}{2} \neq \frac{9}{3}\neq  \frac{11}{4} \neq \frac{13}{5}

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