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Wittaler [7]
2 years ago
13

Please help me I’m stuck on these questions :(

Mathematics
2 answers:
bagirrra123 [75]2 years ago
6 0

Answer:

Step-by-step explanation:

4) Money per hour = Total Money / Total Hours

=> 240 / 8

=> $ 30 Per Hour

5) There is a line formula which is "y = mx + b".

In this, "m" is the slope.

"b" is the y-intercept.

"y" is the y-axis line.

"x" is the x- axis line.

y-intecept means that a point on the graph which has the x value as "0" and y value as anything.

Slope is rise / run.

So, by looking at the graph, we can tell that the y-intecept is (0,0). So, the y-intercept is 0.

Slope = y2 - y1 / x2 - x1

=> 10 - 0 / 2 - 0

=> 10/2

=> 5

So, the equation looks like y = 5x.

6) This is the same question as the above one.

=> Y - intercept = (0,5)

So, the y-intecept is +5.

Now, the equation is  y = mx + 5

=> Slope.

=> Slope of the points (0,5) and (2,8).

We used points (2,8) because the line passes through these points.

=> 8 - 5  /  2 - 0

=> 3 / 2

So, the equation is y = 3/2x + 5

7)  By looking at Rebecca's equation, we can tell that her hourly pay is $9.25.

For Andrew's hourly pay, we need to find the slope of the points.\

Slope = y2 - y1  / x2 - x1

=> 57 - 47.5  /  6 - 5

=> 9.5 / 1

So, the equation for Andrew looks like  y = 9.5x

So, we can tell that Andrew's hourly pay is 9.5.  Rebecca's hourly pay is 9.25

Natasha_Volkova [10]2 years ago
5 0

Answer:

the person above me is right :)

Step-by-step explanation:

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=========================================================

How to get this answer:

Use the unit circle to note that \sin\theta = \cos\theta = \frac{\sqrt{2}}{2} when \theta = \frac{\pi}{4} (aka 45 degrees)

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Here's a more detailed picture of whats going on.

\sin \theta < \cos \theta\\\\\sin \theta < \sqrt{1-\sin^2\theta}\\\\\sin^2 \theta < 1-\sin^2\theta \\\\2\sin^2 \theta < 1\\\\\sin^2 \theta < \frac{1}{2}\\\\\sin \theta < \sqrt{\frac{1}{2}}\\\\\sin \theta < \frac{1}{\sqrt{2}}\\\\\sin \theta < \frac{\sqrt{2}}{2}\\\\\theta < \arcsin\left(\frac{\sqrt{2}}{2}\right)\\\\\theta < \frac{\pi}{4}\\\\

Intersect the intervals 0 \le \theta < \pi and \theta < \frac{\pi}{4} and you'll end up with the final answer 0 \le \theta < \frac{\pi}{4}

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